【发布时间】:2018-07-17 03:39:40
【问题描述】:
我在 GTK+ 3 上的窗口上有一个按钮。单击该按钮时,应该会打开另一个 ui 文件中的窗口,并且应该删除当前窗口的 ui(隐藏)。但我不知道该怎么做。我对 Linux 上的 Gtk+ 编程真的很陌生。 这是我的 .c 文件:
#include <gtk/gtk.h>
static void
buttonClicked(GtkWidget *widget,
gpointer data)
{
//here I need to open another window and close the current one
}
int main (int argc, char *argv[])
{
GtkBuilder *builder;
GObject *window;
GObject *button;
GError *error = NULL;
gtk_init (&argc, &argv);
builder = gtk_builder_new();
if(gtk_builder_add_from_file(builder, "main-window.ui", &error) == 0)
{
g_printerr ("Error loading file: %s\n", error->message);
g_clear_error (&error);
return 1;
}
window = gtk_builder_get_object (builder, "window");
g_signal_connect (window, "destroy", G_CALLBACK (gtk_main_quit), NULL);
button = gtk_builder_get_object (builder, "buttonOpen");
g_signal_connect (button, "clicked", G_CALLBACK (buttonClicked), NULL);
gtk_main ();
return 0;
}
【问题讨论】: