【发布时间】:2020-09-18 22:00:37
【问题描述】:
我正在学习 Kivy,但我不知道如何同时更改屏幕和运行功能。
我应该在哪里声明我的函数,以便按钮可以访问代码并运行函数?
from kivymd.app import MDApp
from kivy.lang.builder import Builder
from kivy.uix.screenmanager import ScreenManager, Screen
screen_helper = """
ScreenManager:
MenuScreen:
FunctionScreen:
<MenuScreen>:
name: 'menu'
MDRectangleFlatButton:
text: 'Function'
pos_hint: {'center_x':0.5,'center_y':0.5}
on_press: root.manager.current = 'function screen'
<FunctionScreen>:
name: 'function screen'
MDRectangleFlatButton:
text: 'Back'
pos_hint: {'center_x':0.5,'center_y':0.1}
on_press: root.manager.current = 'menu'
"""
class MenuScreen(Screen):
pass
class FunctionScreen(Screen):
pass
# Create the screen manager
sm = ScreenManager()
sm.add_widget(MenuScreen(name='menu'))
sm.add_widget(FunctionScreen(name='function'))
class DemoApp(MDApp):
def build(self):
screen = Builder.load_string(screen_helper)
return screen
# def funtion(self):
# do stuff and then go to menu screen
DemoApp().run()
我应该尝试一下,在构建函数中添加 on_opress 属性吗?
你们能帮帮我吗?
【问题讨论】:
标签: python python-3.x kivy kivy-language kivymd