【发布时间】:2019-11-07 23:08:59
【问题描述】:
我正在尝试从 Screenmanager 类的 Screenmanager 调用 Screen 类中的 def,但我不能。
我想在调用 ScreenManager 后立即启动应用程序时制作一个框布局并在该框布局中放置一个按钮,因此它是默认屏幕。 我想这样做,这样我就可以在按下按钮时使用 self.parent.current = 'Screen Name' 在多个屏幕之间切换
这里是代码
class Manager(ScreenManager):
def __init__(self):
self.add_widget(Scr1().make_button())
class Scr1(Screen):
def __init__(self):
self.layout = BoxLayout(orientation = 'vertical')
self.button = Button(text='hello')
self.layout.add_widget(self.button)
def make_button(self, layout):
return self.layout
class MainApp(App):
def build(self):
sm =Manager()
s1 = Scr1()
sm.add_widget=s1
return sm
if __name__ == "__main__":
MainApp().run()
这是我得到的错误
Traceback (most recent call last):
File "C:/Users/user/Desktop/CarsonMusic/Learn.py", line 43, in <module>
MainApp().run()
File "C:\Users\user\AppData\Local\Programs\Python\Python37-32\lib\site-packages\kivy\app.py", line 829, in run
root = self.build()
File "C:/Users/user/Desktop/CarsonMusic/Learn.py", line 37, in build
sm =Manager()
File "C:/Users/user/Desktop/CarsonMusic/Learn.py", line 24, in __init__
self.add_widget(Scr1().make_button())
File "C:\Users\user\AppData\Local\Programs\Python\Python37-32\lib\site-packages\kivy\uix\screenmanager.py", line 979, in add_widget
'ScreenManager accepts only Screen widget.')
kivy.uix.screenmanager.ScreenManagerException: ScreenManager accepts only Screen widget.
我知道我可能犯了一个愚蠢的错误,但有人可以帮助我吗?
【问题讨论】:
标签: python python-3.x kivy