Scapy中的python回调语法错误

Question

我正在尝试运行以下代码。我收到 python 无效语法错误。我正在使用带有 python 2.7.10 的 Mac。有什么问题吗？我对python比较陌生

SyntaxError: 无效语法 callback='parse_item',

完整代码：

# -*- coding: utf-8 -*-
import scrapy

from scrapy.spiders import CrawlSpider
from scrapy.spiders import Rule
from scrapy.linkextractors import Linkextractors

class MpuDivsSpider(CrawlSpider):
    name = 'mpu_divs'
    allowed_domains = ['www.capitalfm.com']
    start_urls = ['http://www.capitalfm.com/']

#http://www.capitalfm.com/music-news/kylie-jenner-outcast-not-made-for-fame/
#http://www.capitalfm.com/artists/adele/news/grenfell-kids-cinema/
#http://www.capitalfm.com/music-news/week-photos/7-august-2017/justin-bieber/
#http://www.capitalfm.com/music-news/week-photos/7-august-2017/leigh-anne-pinnock/
    rules = [

        Rule(LinkExtractor(allow=[r'/7-august-2017/\w*'])
        callback='parse_item',
        follow = True)
    ]

    def parse_item(self, response):
        print response.url

Answer 1

您在19 的行尾忘记了,：

        Rule(LinkExtractor(allow=[r'/7-august-2017/\w*']),