【发布时间】:2018-10-20 02:18:31
【问题描述】:
如何正确地为 switch_id 和 switch_id_popup 创建活动属性,以便可以在 timer_loop 内使用 kivy 时钟创建条件语句?
我在一个类似问题上得到了很好的反馈(再次感谢 eyllanesc),但由于涉及弹出窗口,我无法采纳建议。
下面是说明我的问题的草图。我已经用箭头标识了所有有问题的区域。预先感谢您的任何帮助。
from kivy.app import App
from kivy.lang import Builder
from kivy.clock import Clock
import time
from kivy.uix.popup import Popup
theRoot = Builder.load_string('''
<CustomPopup1>:
StackLayout:
active2: switch_id_popup.active #<---- switch_id_popup declared here(active2)
Switch: #<---- This switch (switch_id_popup)
id: switch_id_popup
size_hint: .5, .5
active: switch_id_popup.active
Button:
text: 'Close'
on_release: root.dismiss()
size_hint: .5, .5
StackLayout:
active1: switch_id.active #<---- switch_id declared here(active1)
orientation: 'lr-tb'
padding: 10
spacing: 5
Label:
text: "Zone 1 Valve"
size_hint: .25, .1
Switch: #<---- This switch (switch_id)
id: switch_id
size_hint: .25, .1
active: switch_id.active
Button:
text: "Program 1"
on_press: app.open_popup1()
size_hint: .5,.1
''')
class CustomPopup1(Popup):
pass
class theApp(App):
def build(self):
Clock.schedule_interval(self.timer_loop, 2)
return theRoot
def timer_loop(self, dt):
if theRoot.active1 and theRoot.active2: #<---- How do I make this work if switch_id_popup is within a popup?
print("Do something")
else:
print("Do nothing")
def open_popup1(self):
the_popup = CustomPopup1()
the_popup.open()
if __name__ == '__main__':
theApp().run()
【问题讨论】:
标签: python kivy kivy-language