【发布时间】:2018-11-13 14:48:54
【问题描述】:
我有以下类型的集合
{
"_id" : ObjectId("5bbb299f06229dddbaab553b"),
"phone" : "+38 (031) 231-23-21",
"date_call" : "2018-10-08",
"adress_delivery" : "1",
"quantity_concrete" : "1",
"state" : "200",
"comments" : "1",
"is_order" : "n",
"date_delivery" : "",
"quantity_orders" : "",
"summ_order" : "",
"profit" : "",
"id" : "0"
}
在终端请求时
db.getCollection("customers").find(
{
"$and" : [
{
"date_call" : {
"$lte" : "2018-10-10"
}
},
{
"date_call" : {
"$gte" : "2018-09-24"
}
}
]
},
{
"phone" : 1,
"is_order" : 1
}
);
我得到了答案
{
"_id" : ObjectId("5bbb299f06229dddbaab553b"),
"phone" : "+38 (031) 231-23-21",
"is_order" : "n"
}
当在 nodeJS 中请求相同的查询时
client.db(“mongoDB”).collection("customers").find(
{
"$and": [
{
"date_call": {
"$lte" : "2018-10-14"
}
},
{
"date_call": {
"$gte" : "2018-09-24"
}
}
]
},
{
“phone”: 1,
"is_order": 1
}
)
我得到一个完整的答案,而不是查询中设置的“电话”和“is_order”。请告诉我如何才能只获取指定的数据?
【问题讨论】:
-
通过 {fields:{"phone": 1, "is_order":1}} 作为投影对象