【问题标题】:ECEF from Azimuth, Elevation, Range and Observer Lat,Lon,AltECEF 来自方位角、仰角、范围和观察者 Lat、Lon、Alt
【发布时间】:2013-04-11 17:18:40
【问题描述】:

我正在尝试编写一个基本的 Python 脚本,该脚本将从给定位置跟踪使用 tle 定义的给定卫星。我不是一个 asto/orbital 人,但我正在努力变得更聪明。

当我尝试将方位角、仰角、距离值转换为 ECEF 位置时遇到问题。我正在使用 PyEphem 来获取观察值,并使用 spg4 来获取要验证的真实位置。我也在使用网站http://www.n2yo.com/?s=25544 来验证值。

我正在通过以下方式获取观察到的方位角、仰角和范围:

def get_ob(epoch, sv, obsLoc):
    site = ephem.Observer()
    site.lon = str(obsLoc.lat)   # +E -104.77 here
    site.lat = str(obsLoc.lon)   # +N 38.95   here
    site.elevation = obsLoc.alt # meters    0 here
    #epoch = time.time()
    site.date = datetime.datetime.utcfromtimestamp(epoch)

    sat = ephem.readtle(sv.name,sv.tle1,sv.tle2)
    sat.compute(site)

    az       = degrees(sat.az)
    el       = degrees(sat.alt)
    #range in m
    range    = sat.range
    sat_lat  = degrees(sat.sublat)
    sat_long = degrees(sat.sublong)
    # elevation of sat in m
    sat_elev = sat.elevation

    x, y, z    = aer2ecef(az,el,range,38.95,-104.77,80 / 1000)

报告的方位角、仰角和范围与网站相符。我正在转换为 ECEF 职位:

def aer2ecef(azimuthDeg, elevationDeg, slantRange, obs_lat, obs_long, obs_alt):

    #site ecef in meters
    sitex, sitey, sitez = llh2ecef(obs_lat,obs_long,obs_alt)

    #some needed calculations
    slat = sin(radians(obs_lat))
    slon = sin(radians(obs_long))
    clat = cos(radians(obs_lat))
    clon = cos(radians(obs_long))

    azRad = radians(azimuthDeg)
    elRad = radians(elevationDeg)

    # az,el,range to sez convertion
    south  = -slantRange * cos(elRad) * cos(azRad)
    east   =  slantRange * cos(elRad) * sin(azRad)
    zenith =  slantRange * sin(elRad)


    x = ( slat * clon * south) + (-slon * east) + (clat * clon * zenith) + sitex
    y = ( slat * slon * south) + ( clon * east) + (clat * slon * zenith) + sitey
    z = (-clat *        south) + ( slat * zenith) + sitez

    return x, y, z

当我绘制它时,位置偏离了(地球的错误一侧)。我从网站和 spg4 中得到的位置匹配,所以我相信这些是正确的。

我不确定错误是在我的转换方法中,还是我使用了错误的数据进行转换。我在这里的答案中找到了该方法:Get ECEF XYZ given starting coordinates, range, azimuth, and elevation

任何关于我下车地点的建议或建议将不胜感激。下面是测试输入/输出:

我正在测试的卫星是 ISS 和 directv10(一颗固定,一颗移动 - 可通过互联网跟踪进行验证):

0 Direct10
1 31862U 07032A   13099.15996183 -.00000126  00000-0  10000-3 0  1194
2 31862 000.0489 046.9646 0000388 001.7833 103.5813 01.00271667 21104
0 ISS
1 25544U 98067A   13112.50724749  .00016717  00000-0  10270-3 0  9148
2 25544  51.6465  24.5919 0009906 171.1474 188.9854 15.52429950 26067

观察者网站lla:

[38.95 -104.77 0.0]

结果:

sv: ISS ephem observed response(km)              @ epoch: 1365630559.000000 : [344.067992722211, -72.38297754053431, 12587.123][degrees(sat.az), degrees(sat.alt), sat.range]
sv: ISS ephem reported llh location(km)          @ epoch: 1365630559.000000 : [-41.678271938092195, -129.16682754513502, 421.06290625][degrees(sat.sublat0, degrees(sat.sublong), sat.elevation]
sv: ISS ephem calculated xyz location(km)        @ epoch: 1365630559.000000 : [688.24385373837845, 6712.2004971137103, -704.83633267710866][aer2ecef(az,el,range,obsLoc.lat,obsLoc.lon,obsLoc.alt)]
sv: ISS ephem llh from calc xyz location(km)     @ epoch: 1365630559.000000 : [-6.001014287867631, 84.1455657632957, 12587.123][ecef2llh()]
sv: ISS ephem xyz from reported llh location(km) @ epoch: 1365630559.000000 :[-3211.7910504146325, -3942.7032969856118, -4498.9656030253745][llh2ecef(lat,long,elev)]
sv: ISS spg84 ecef position(m) @ epoch: 1365630559.000000 : [-3207667.3380003194, -3936704.823960199, -4521293.5388663234]
sv: ISS spg84 ecef2llh(m)      @ epoch: 1365630559.000000 : [-41.68067424524357, -129.17349987675482, 6792812.8704163525]
sv: Direct10 ephem observed response(km)              @ epoch: 1365630559.000000 : [320.8276456938389, -19.703680198781303, 43887.572][degrees(sat.az), degrees(sat.alt), sat.range]
sv: Direct10 ephem reported llh location(km)          @ epoch: 1365630559.000000 : [0.004647324660923812, -102.8070784813048, 35784.688][degrees(sat.sublat0, degrees(sat.sublong), sat.elevation]
sv: Direct10 ephem calculated xyz location(km)        @ epoch: 1365630559.000000 : [-18435.237655222769, 32449.238763035213, 19596.893001978762][aer2ecef(az,el,range,obsLoc.lat,obsLoc.lon,obsLoc.alt)]
sv: Direct10 ephem llh from calc xyz location(km)     @ epoch: 1365630559.000000 : [27.727834453026748, 119.60200825103102, 43887.572][ecef2llh()]
sv: Direct10 ephem xyz from reported llh location(km) @ epoch: 1365630559.000000 :[-9346.1899009219123, -41113.897098582587, 3.4164105611003754][llh2ecef(lat,long,elev)]
sv: Direct10 spg84 ecef position(m) @ epoch: 1365630559.000000 : [-9348605.9260040354, -41113193.982686974, -14060.29781505302]
sv: Direct10 spg84 ecef2llh(m)      @ epoch: 1365630559.000000 : [-0.019106864351793953, -102.81049179145006, 42156299.077687651]

【问题讨论】:

    标签: coordinate-transformation astronomy satellite pyephem


    【解决方案1】:

    我觉得自己很笨但发现了问题......

    我正在将站点中的纬度和经度转换为 PyEphem 模型(查看第 3-4 行)...目前转换工作正常。

    让孩子们上一课。使用好的变量名...不要像我一样懒惰,浪费时间试图找到一个不存在的数学错误....

    【讨论】:

    • 随着年龄的增长,我的变量名越来越长!
    • 我想获得类似的东西,但不使用输入“tle”,而是使用卫星的笛卡尔坐标XYZ,并获得sat_lat、sat_long和range。换句话说,卫星的轨道信息,然后获得该卫星下一系列历元的地面经度/纬度。如何规避上述“sat = ephem.readtle(sv.name,sv.tle1,sv.tle2)”?这是我最想做的,没有 sv.tle 作为输入(我有笛卡尔坐标)。
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