【发布时间】:2016-06-20 17:35:27
【问题描述】:
我正在构建一个带有加载器的 web 视图 android 应用程序,但我希望当用户单击 web 视图网站的任何链接或按钮时,然后显示加载器,直到响应出现,所以该怎么做。
public class MainActivity extends Activity {
/** Called when the activity is first created. */
WebView web;
ProgressBar progressBar;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
web = (WebView) findViewById(R.id.webview01);
progressBar = (ProgressBar) findViewById(R.id.progressBar1);
web.setWebViewClient(new myWebClient());
web.getSettings().setJavaScriptEnabled(true);
web.loadUrl("http://www.example.com");
}
public class myWebClient extends WebViewClient
{
@Override
public void onPageStarted(WebView view, String url, Bitmap favicon) {
// TODO Auto-generated method stub
super.onPageStarted(view, url, favicon);
}
@Override
public boolean shouldOverrideUrlLoading(WebView view, String url) {
// TODO Auto-generated method stub
view.loadUrl(url);
return true;
}
@Override
public void onPageFinished(WebView view, String url) {
// TODO Auto-generated method stub
super.onPageFinished(view, url);
progressBar.setVisibility(View.GONE);
}
}
// To handle "Back" key press event for WebView to go back to previous screen.
@Override
public boolean onKeyDown(int keyCode, KeyEvent event)
{
if ((keyCode == KeyEvent.KEYCODE_BACK) && web.canGoBack()) {
web.goBack();
return true;
}
return super.onKeyDown(keyCode, event);
}
}
【问题讨论】:
标签: java android webview android-developer-api