如何制作运行功能的可点击 UIImages？（Swift）

Question

（我几天前才开始使用 Swift，对编程比较陌生，所以请多多包涵。）我正在尝试让随机块出现在屏幕上，用户必须点击它们才能使它们消失。我已经能够创建块，但我不知道如何真正使它们可点击。有人可以帮帮我吗？到目前为止，这是我的代码：

func createBlock(){

    let imageName = "block.png"
    let image = UIImage(named: imageName)
    let imageView = UIImageView(image: image!)

    imageView.frame = CGRect(x: xPosition, y: -50, width: size, height: size)
    self.view.addSubview(imageView)

    UIView.animateWithDuration(duration, delay: delay, options: options, animations: {

        imageView.backgroundColor = UIColor.redColor()
        imageView.frame = CGRect(x: self.xPosition, y: 590, width: self.size, height: self.size)

        }, completion: { animationFinished in


            imageView.removeFromSuperview()
            self.life-=1


    })



}

我想让方块在被点击时消失；关于如何做到这一点的任何建议？

Answer 1

这非常简单，只需使用 UITapGestureRecognizer。我通常将识别器初始化为全局变量。

let tapRecognizer = UITapGestureRecognizer()

然后在你的 viewDidLoad 中：

// Replace with your function
tapRecognizer.addTarget(self, action: "removeBlock")
imageView.addGestureRecognizer(tapRecognizer)

Answer 2

func removeImage(gesture: UIGestureRecognizer) {
    gesture.view?.removeFromSuperview()
}

func createBlock() {
    let imageName = "block.png"
    let image = UIImage(named: imageName)
    let imageView = UIImageView(image: image!)

    imageView.frame = CGRect(x: xPosition, y: -50, width: size, height: size)

    imageView.userInteractionEnabled = true                       // IMPORTANT
    imageView.addGestureRecognizer(UITapGestureRecognizer(target: self, action: "removeImage:"))

    self.view.addSubview(imageView)

    UIView.animateWithDuration(duration, delay: delay, options: options, animations: {

        imageView.backgroundColor = UIColor.redColor()
        imageView.frame = CGRect(x: self.xPosition, y: 590, width: self.size, height: self.size)

    }, { _ in
        imageView.removeFromSuperview()
        self.life-=1
    })
}

注意imageView.userInteractionEnabled = true 这真的很重要，因为这将允许该视图上的触摸事件，它在 UIImgageView 中设置为 false 作为默认值。