【发布时间】:2017-01-06 10:15:43
【问题描述】:
按字母顺序排列文件夹和文件的列表视图
我正在尝试以下代码
public class MainActivity extends ActionBarActivity {
private File file;
private List<String> myList;
private ListView listView;
private TextView pathTextView;
private String mediapath = new String(Environment.getExternalStorageDirectory().getAbsolutePath());
private final static String[] acceptedExtensions= {"mp3", "mp2", "wav", "flac", "ogg", "au" , "snd", "mid", "midi", "kar"
, "mga", "aif", "aiff", "aifc", "m3u", "oga", "spx"};
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
listView=(ListView) findViewById(R.id.pathlist);
pathTextView=(TextView) findViewById(R.id.path);
myList = new ArrayList<String>();
String root_sd = Environment.getExternalStorageDirectory().toString();
Log.e("Root",root_sd);
String state = Environment.getExternalStorageState();
File list[] = null ;
/* if ( Environment.MEDIA_MOUNTED.equals(state) || Environment.MEDIA_MOUNTED_READ_ONLY.equals(state) ) { // we can read the External Storage...
list=getAllFilesOfDir(Environment.getExternalStorageDirectory());
}*/
pathTextView.setText(root_sd);
file = new File( root_sd ) ;
list = file.listFiles(new AudioFilter());
Log.e("Size of list ","" +list.length);
//LoadDirectory(root_sd);
for( int i=0; i< list.length; i++)
{
String name=list[i].getName();
int count = getAudioFileCount(list[i].getAbsolutePath());
Log.e("Count : "+count, list[i].getAbsolutePath());
if(count!=0)
myList.add(name);
/*int count=getAllFilesOfDir(list[i]);
Log.e("Songs count ",""+count);
*/
}
listView.setAdapter(new ArrayAdapter<String>(this,
android.R.layout.simple_list_item_1, myList ));
listView.setOnItemClickListener(new OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> arg0, View arg1, int position,
long arg3) {
File temp_file = new File( file, myList.get( position ) );
if( !temp_file.isFile())
{
//LoadDirectory(myList.get( position ));
file = new File( file, myList.get( position ));
File list[] = file.listFiles(new AudioFilter());
myList.clear();
for( int i=0; i< list.length; i++)
{
String name=list[i].getName();
int count = getAudioFileCount(list[i].getAbsolutePath());
Log.e("Count : "+count, list[i].getAbsolutePath());
if(count!=0)
myList.add(name);
/*int count=getAllFilesOfDir(list[i]);
Log.e("Songs count ",""+count);
if(count!=0)
myList.add(name);*/
}
pathTextView.setText( file.toString());
//Toast.makeText(getApplicationContext(), file.toString(), Toast.LENGTH_LONG).show();
listView.setAdapter(new ArrayAdapter<String>(MainActivity.this, android.R.layout.simple_list_item_1, myList ));
}
}
});
}
它给了我所有歌曲的文件和文件夹
但是,如果一个文件夹同时包含子文件夹和歌曲,我想对列表视图进行排序以首先显示所有子文件夹,然后是该文件夹中的所有歌曲
如何做到这一点
【问题讨论】:
-
您如何区分文件和文件夹
-
它检查 temp_file 中的文件夹或文件
if( !temp_file.isFile()) -
如果是文件夹就会进入这个if条件?那么文件呢?