【发布时间】:2017-02-14 07:23:15
【问题描述】:
我已经发布了这个问题,但即使我再次编辑我的帖子也没有人提供解决方案,所以我删除并再次发布。
我不太了解 StringRequest 类的工作原理及其响应。请通过简单且适当的指南帮助我。它响应单个 Jsonobject 但不响应数组。 在这个 json 响应中,我不知道如何捕获该数组然后在 Listview 上设置的数据数组
服务器响应
I/System.out:
{
"success":true,"first_name":"savha","last_name":"jiii","mobile":2147483647
}
W/System.err: org.json.JSONException:
Value
{
"success":true,"first_name":"savha","last_name":"jiii","mobile":2147483647
}
of type org.json.JSONObject cannot be converted to JSONArray
Json StringRequest Volley
php代码
< ?php
$con=mysqli_connect(XXXXXXXXXXXXXX);
$state=$_POST["state"];
$dist=$_POST["dist"];
$statement=mysqli_prepare($con,"SELECT first_name,last_name,mobile FROM first WHERE state=? AND dist=?");
mysqli_stmt_bind_param($statement,"ss",$state,$dist);
mysqli_stmt_execute($statement);
mysqli_stmt_store_result($statement);
mysqli_stmt_bind_result($statement,$fname,$lname,$mobile);
$response=array();
$response["success"]=false;
while(mysqli_stmt_fetch($statement))
{
$response["success"]=true;
$response["first_name"]=$fname;
$response["last_name"]=$lname;
$response["mobile"]=$mobile;
}
echo json_encode($response);
?>
ServiceRequest 类
public class SevakRequest extends StringRequest {
private static final String LOGIN_REQUEST_URL="http://XXXXXX.php";
private Map<String ,String> params;
public SevakRequest(String state,String dist, Response.Listener<String> listener)
{
super(Method.POST,LOGIN_REQUEST_URL,listener,null);
params=new HashMap<>();
// params.put("service",service);
params.put("state",state);
params.put("dist",dist);
}
@Override
public Map<String, String> getParams() {
return params;
}
}
MainActivity 类
public class SearchResult extends Activity {
Button btn1,btn2;
ListView lv1;
TextView tv1;
String serv, stat, dist;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_search_result);
btn1 = (Button) findViewById(R.id.btn1);
btn2 = (Button) findViewById(R.id.btn2);
lv1 = (ListView) findViewById(R.id.lv1);
tv1 = (TextView) findViewById(R.id.tv1);
Intent in = getIntent();
serv = in.getStringExtra("key1");
stat = in.getStringExtra("key2");
dist = in.getStringExtra("key3");
tv1.setText(serv + " >> " + stat + " >> " + dist);
Response.Listener<String> listener = new Response.Listener<String>() {
@Override
public void onResponse(String response) {
try {
JSONObject jsonResponse = new JSONObject(response);
boolean success = jsonResponse.getBoolean("success");
if (success) {
JSONArray jsonArray = new JSONArray(response);
int length = jsonArray.length();
List<String> listContents = new ArrayList<String>(length);
for (int i = 0; i < length; i++) {
String fname = jsonResponse.getString("first_name").toString();
String lname = jsonResponse.getString("last_name").toString();
String mobile = jsonResponse.getString("mobile").toString();
listContents.add("First name: " + fname + "\nLast name: " + lname + "\nMobile: " + mobile);
}
lv1.setAdapter(new ArrayAdapter<String>(getApplicationContext(), android.R.layout.simple_list_item_1, listContents));
} else {
Toast.makeText(getApplicationContext(), "Error occurred", Toast.LENGTH_LONG).show();
}
} catch (JSONException e) {
e.printStackTrace();
}
}
};
SevakRequest sevakRequest = new SevakRequest(stat, dist, listener);
RequestQueue queue = Volley.newRequestQueue(getApplicationContext());
queue.add(sevakRequest);
}
}
【问题讨论】:
-
发布您的服务器响应。
-
I/System.out: { "success":true,"first_name":"savha","last_name":"jiii","mobile":2147483647 } W/System.err: org.json.JSONException: Value { "success":true,"first_name":"savha","last_name":"jiii","mobile":2147483647 } of type org.json.JSONObject cannot be converted to JSONArray -
问题中添加了响应
-
您在 json 响应中收到一个单一对象。解析的第一部分是正确的
JSONObject jsonResponse = new JSONObject(response);,但在此之后您再次尝试将其放入数组中。它使您期待与您收到的不同的东西。如果我理解你的 php 代码是正确的,那么还有一个错误,你总是覆盖 $response 数组中的相同字段。 -
它清楚地表明你的响应是 JSONObject 而不是 JSONArray
标签: php android json listview android-volley