选择联系人时如何解决类型不匹配错误？

Question

在这一行

val contactUri: Uri? = data.data
…
val cursor = requireActivity().contentResolver
    .query(**contactUri**, queryFields, null, null, null)

类型不匹配需要 Uri got Uri

你如何解决这个问题？

代码示例

override fun onActivityResult(requestCode: Int, resultCode: Int, data: Intent?) {
    when {
        resultCode != Activity.RESULT_OK -> return

        requestCode == REQUEST_CONTACT && data != null -> {
            val contactUri: Uri? = data.data
            // Specify which fields query to return values for.
            val queryFields = arrayOf(ContactsContract.Contacts.DISPLAY_NAME)
            // Perform query
            val cursor = requireActivity().contentResolver
                .query(contactUri, queryFields, null, null, null)
            cursor?.use {
                // Double-check that you actually got results
                if (it.count == 0) {
                    return
                }

                // Pull out the first column of the first row of data
                it.moveToFirst()
                val suspect = it.getString(0)
                crime.suspect = suspect
                crimeDetailViewModel.saveCrime(crime)
                suspectButton.text = suspect
            }
        }
    }
}

Answer 1

要么尝试删除？在你的 uri 之后：

val contactUri: Uri = data.data

而不是

val contactUri: Uri? = data.data

或者如果这不起作用，check this answer out