用于将一个表的行聚合到另一个表的 MySQL 触发器答案

【问题标题】：MySQL Trigger for aggregating one table's rows to another table用于将一个表的行聚合到另一个表的 MySQL 触发器
【发布时间】：2017-06-24 11:37:17
【问题描述】：

我有 2 个 MySQL 表，一个将使用需要聚合的新行进行更新（表 1）。还有一个应该使用 mysql 触发器自动填充聚合数据（表 2）。

给定表格架构：

表 1 的示例：要聚合的表

唯一键uniqueid (uniqueid,ci,ai,status)

表 2 的示例：汇总表

唯一键IX_Unique_daily (ai,ci,day)

SQL 触发器应该是这样的：

分隔符 $$

创建插入后触发yii_botclient2.st_unqiue_trigger 开yii_botclient2.st_unique 每一行开始

SET @myDay := DATE(NEW.date);
SET @today = DATE();
SET isDaily := SELECT COUNT(id) FROM `yii_botclient2`.`st_daily` WHERE `ai` = NEW.ai AND st_daily.ci = NEW.ci AND st_daily.day = @myDay;
SET myDaily = IFNULL(isDaily, 'No');

IF (myDaily = 'No') THEN
    IF NEW.status = 0
        INSERT INTO st_daily (`day`, `ai`,`ci`,`impressions`,`updated`) VALUES (@today,NEW.ai,NEW.ci,1,NOW());
    ELSEIF NEW.status = 1 
        INSERT INTO st_daily (`day`, `ai`,`ci`,`clicks`,`updated`) VALUES (@today,NEW.ai,NEW.ci,1,NOW());
    ELSEIF NEW.status = 2
        INSERT INTO st_daily (`day`, `ai`,`ci`,`leads`,`updated`) VALUES (@today,NEW.ai,NEW.ci,1,NOW());
    ELSEIF NEW.status = 3 
        INSERT INTO st_daily (`day`, `ai`,`ci`,`ftds`,`updated`) VALUES (@today,NEW.ai,NEW.ci,1,NOW());
    END IF;
ELSE
    IF NEW.status = 0
        UPDATE st_daily SET `impressions` = `impressions` + 1 WHERE st_daily.ci = NEW.ci AND st_daily.ai = NEW.ai AND st_daily.day = @myDay;
    ELSEIF NEW.status = 1 
        UPDATE st_daily SET `clicks` = `clicks` + 1 WHERE st_daily.ci = NEW.ci AND st_daily.ai = NEW.ai AND st_daily.day = @myDay;
    ELSEIF NEW.status = 2
        UPDATE st_daily SET `leads` = `leads` + 1 WHERE st_daily.ci = NEW.ci AND st_daily.ai = NEW.ai AND st_daily.day = @myDay;
    ELSEIF NEW.status = 3 
        UPDATE st_daily SET `ftds` = `ftds` + 1 WHERE st_daily.ci = NEW.ci AND st_daily.ai = NEW.ai AND st_daily.day = @myDay;
    END IF;
END IF;

END$$

分隔符;

您能帮忙解决一下 MySQL 触发器吗？

【问题讨论】：

你有什么问题？
我无法执行触发器查询，我不明白它有什么问题

标签： mysql sql triggers aggregation

【解决方案1】：

声明变量，在 set 语句中使用 =，Date 函数需要一个参数，if 语句需要 then 这样的东西编译到它抱怨表不存在的地步，如果您需要任何进一步的帮助，请将问题中的表作为文本或 sql fiddle 提供。

drop trigger if exists st_unqiue_trigger; 

DELIMITER $$

CREATE TRIGGER yii_botclient2.st_unqiue_trigger AFTER INSERT ON st_unique FOR EACH ROW BEGIN
declare myday date;
declare today  date;
declare isdaily int;
declare mydaily varchar(2);
SET myDay = DATE(NEW.date);
SET today = date(now());
SELECT COUNT(id) into isdaily FROM `yii_botclient2`.`st_daily` WHERE `ai` = NEW.ai AND st_daily.ci = NEW.ci AND st_daily.day = myDay;
SET myDaily = IFNULL(isDaily, 'No');

IF (myDaily = 'No') THEN
    IF NEW.status = 0 then
        INSERT INTO st_daily (`day`, `ai`,`ci`,`impressions`,`updated`) VALUES (today,NEW.ai,NEW.ci,1,NOW());
    ELSEIF NEW.status = 1 then
        INSERT INTO st_daily (`day`, `ai`,`ci`,`clicks`,`updated`) VALUES (today,NEW.ai,NEW.ci,1,NOW());
    ELSEIF NEW.status = 2 then
        INSERT INTO st_daily (`day`, `ai`,`ci`,`leads`,`updated`) VALUES (today,NEW.ai,NEW.ci,1,NOW());
    ELSEIF NEW.status = 3 then
        INSERT INTO st_daily (`day`, `ai`,`ci`,`ftds`,`updated`) VALUES (today,NEW.ai,NEW.ci,1,NOW());
    END IF;
ELSE
    IF NEW.status = 0 then
        UPDATE st_daily SET `impressions` = `impressions` + 1 WHERE st_daily.ci = NEW.ci AND st_daily.ai = NEW.ai AND st_daily.day = myDay;
    ELSEIF NEW.status = 1 then
        UPDATE st_daily SET `clicks` = `clicks` + 1 WHERE st_daily.ci = NEW.ci AND st_daily.ai = NEW.ai AND st_daily.day = myDay;
    ELSEIF NEW.status = 2 then
        UPDATE st_daily SET `leads` = `leads` + 1 WHERE st_daily.ci = NEW.ci AND st_daily.ai = NEW.ai AND st_daily.day = myDay;
    ELSEIF NEW.status = 3 then
        UPDATE st_daily SET `ftds` = `ftds` + 1 WHERE st_daily.ci = NEW.ci AND st_daily.ai = NEW.ai AND st_daily.day = myDay;
    END IF;
END IF;

END $$

delimiter ;

【讨论】：