【问题标题】:SQLSTATE[23000]SQLSTATE[23000]
【发布时间】:2016-03-03 04:36:39
【问题描述】:

我对 laravel 的 phpmyadmin 有问题 我想通过控制器更新数据库视图中的数据,但发生错误

    // save all seats
    foreach ($request->all() as $key => $param) {
        if ($key === '_token') continue;

        $data = explode('-', $key);

        $bs = new BookedSeat();
        $bs->booking_id = $booking->id;
        $bs->day_id = str_replace('c', '', $data[0]);
        $bs->table_id = str_replace('t', '', $data[1]);
        $bs->number = 0;
        $bs->status = 'requested';
        $bs->save();
    }

its an error when i try update data

its my db

【问题讨论】:

  • 请分享你的插入数据代码,需要插入day_id外键

标签: laravel controller phpmyadmin foreign-keys relationship


【解决方案1】:

更新

 // save all seats
foreach ($request->all() as $key => $param) {
    if ($key === '_token') continue;

    $data = explode('-', $key);

    $bs = new BookedSeat();
    $bs->booking_id = $booking->id;
    $day = DB::table('days')->where('name',$data[0])->get(); 
    $bs->day_id = $day->id;
    $bs->table_id = str_replace('t', '', $data[1]);
    $bs->number = 0;
    $bs->status = 'requested';
    $bs->save();
}

【讨论】:

  • 嗨,朋友。书的 id 或 id 是书
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