【发布时间】:2016-03-03 04:36:39
【问题描述】:
我对 laravel 的 phpmyadmin 有问题 我想通过控制器更新数据库视图中的数据,但发生错误
// save all seats
foreach ($request->all() as $key => $param) {
if ($key === '_token') continue;
$data = explode('-', $key);
$bs = new BookedSeat();
$bs->booking_id = $booking->id;
$bs->day_id = str_replace('c', '', $data[0]);
$bs->table_id = str_replace('t', '', $data[1]);
$bs->number = 0;
$bs->status = 'requested';
$bs->save();
}
【问题讨论】:
-
请分享你的插入数据代码,需要插入
day_id外键
标签: laravel controller phpmyadmin foreign-keys relationship