传递soap对象（soap1.2）android时无法从HttpResponse获取响应？答案

【问题标题】：unable to get Response from HttpResponse when passing soap object (soap1.2) android?传递soap对象（soap1.2）android时无法从HttpResponse获取响应？
【发布时间】：2013-08-02 13:34:18
【问题描述】：

代码：

            String response ;
            try {
                final String SOAP_ACTION = "http://tempuri.org/myAction";
                final String URL = "MYURL";
                HttpClient httpClient = new DefaultHttpClient();
                HttpPost httpPost = new HttpPost(URL);
                String bodyOut = "<soapenv:Envelope xmlns:soapenv=\"http://schemas.xmlsoap.org/soap/envelope/\" xmlns:tem=\"http://tempuri.org/\">"
                        + "   <soapenv:Header/>"
                        + "   <soapenv:Body>"
                        ........ MY Data.......
                        + "      </tem:Login>"
                        + "   </soapenv:Body>" + "</soapenv:Envelope>";

                StringEntity se = new StringEntity(bodyOut, HTTP.UTF_8);
                    //StringEntity se = new StringEntity(request1, HTTP.UTF_8); 
                se.setContentType("text/xml");
                httpPost.addHeader("SOAPAction", SOAP_ACTION);
                httpPost.setEntity(se);

                HttpResponse httpResponse = httpClient.execute(httpPost);
                HttpEntity resEntity = httpResponse.getEntity();
                response = EntityUtils.toString(resEntity);
                if (response != null) {
                    Log.i("Response", "" + response);// this is not being printed
                    Log.i("test response", "not null");// this is being printed
                }
                else
                    Log.i("Response", "null");
            } catch (Exception e) {
                e.printStackTrace();
            }

没有例外，但是：Log.i("Response", "" + response);// this is not being printed

LogCat：

08-02 19:04:51.929: I/test response(20413): not null

【问题讨论】：

记录httpResponse.getStatusLine()。这表示您的消息无法处理。
@Raghunandan 谢谢 :)，你说得对，我收到了HTTP/1.1 400 BadRequest
stackoverflow.com/questions/8087515/…。检查这个接近你的错误状态
@Raghunandan 当我尝试使用se.setContentType("application/soap+xml"); 而不是se.setContentType("text/xml"); 时出现错误请求
很高兴知道，甚至更好，因为您发布的解决方案将帮助其他人接受它

标签： android soap httpresponse soap1.2

【解决方案1】：

作为它的wsHttpBindingWCF service Android

所以我已经使用以下方法解决了这个问题：

String METHOD_NAME = "MyMethodName"; 
String NAMESPACE = "http://tempuri.org/"; 
String URL = "MyUr;";
String SOAP_ACTION = "http://tempuri.org/MySoapAction"; 



SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);

PropertyInfo req = new PropertyInfo();
req.name = "xmlstring";
req.namespace = NAMESPACE;
req.type = String.class;
req.setValue("........ MY Data.......");// without these `tags <soapenv:`
request.addProperty(req);

Element e = new Element();
e.setName("To");
e.setNamespace("http://www.w3.org/2005/08/addressing");
e.addChild(Node.TEXT,"MyUrl");

Element e1 = new Element();
e1.setName("Action");
e1.setNamespace("http://www.w3.org/2005/08/addressing");
e1.addChild(Node.TEXT,
        "http://tempuri.org/SoapAction");

SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(
        SoapEnvelope.VER12);
envelope.dotNet = true;
envelope.headerOut = new Element[] { e, e1 };
envelope.setOutputSoapObject(request);

HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);
androidHttpTransport.call(SOAP_ACTION, envelope);
SoapPrimitive result = (SoapPrimitive) envelope.getResponse();

String resultData = result.toString();
Log.i("Result", "" + resultData);

【讨论】：