【发布时间】:2016-04-14 16:15:28
【问题描述】:
我正在尝试创建显示来自 IP 摄像机的视频的程序。
这是我的代码:
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Windows.Forms;
using Emgu.CV; //
using Emgu.CV.CvEnum; // usual Emgu Cv imports
using Emgu.CV.Structure; //
using Emgu.CV.UI;
using System.IO;
using System.Reflection;
using System.Windows;
using System.Runtime.InteropServices;
using Emgu.Util;
using System.Net;
namespace WindowsFormsApplication1
{
public partial class Main : Form
{
public Main()
{
InitializeComponent();
}
public Capture _capture;
public Mat imgOriginal;
private void imageBox2_Click(object sender, EventArgs e)
{
}
private void label1_Click(object sender, EventArgs e)
{
}
public void button1_Click(object sender, EventArgs e)
{
_capture = new Capture("http://192.168.1.148:8080/video");
_capture.ImageGrabbed += ProcessFrame;
_capture.Start();
}
public void ProcessFrame(object sender, EventArgs arg)
{
imgOriginal= _capture.QueryFrame();
ibOriginal.Image = imgOriginal;
}
}
}
这一步卡住了(意料之外):
imgOriginal= _capture.QueryFrame();
也许我应该调用方法,但我不知道怎么做。 我正在使用 Emgu 3.1.0 Link to Doc
【问题讨论】:
标签: c# video emgucv invoke opencv3.0