从控制台创建 WebAPI 帖子以在 json 数据中包含 $type答案

【问题标题】：Create WebAPI post from Console to include $type in json data从控制台创建 WebAPI 帖子以在 json 数据中包含 $type
【发布时间】：2014-03-05 20:39:22
【问题描述】：

我正在创建对象并将它们发布到 webapi。基本上我只是无法让这些该死的东西序列化，以便在 json 中包含 $type 信息。以下是我正在尝试编写的代码。之后是我期望的json。

       var cds = new List<CreditDefaultSwaps>()
        {
            new CreditDefaultSwaps() { ModelNumber = "SP8A1ETA", BrokerSpread = 0},
            new CreditDefaultSwaps() { ModelNumber = "SP3A0TU1", BrokerSpread = 0},
            new CreditDefaultSwaps() { ModelNumber = "SP4A102V", BrokerSpread = 0}
        };

        var client = new HttpClient {BaseAddress = new Uri("http://localhost/BloombergWebAPI/api/")};

        client.DefaultRequestHeaders.Accept.Clear();
        client.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("application/json"));

        // set up request object
        var oContract = new WebApiDataServiceRequest
        {
            RequestType = ReferenceDataRequestServiceTypes.ReferenceDataRequest,
            SwapType = BloombergWebAPIMarshal.SwapType.CDS,
            SecurityList = cds
        };

        Tried something like this and the var content was formatted as I would expect
        however I couldn't post the data using postasjsonasync

        //var content = JsonConvert.SerializeObject(oContract, Formatting.Indented,
        //    new JsonSerializerSettings { TypeNameHandling = TypeNameHandling.Objects });

           Console.ReadLine();

        var response = client.PostAsJsonAsync("bloombergapi/processbloombergrequest", oContract).Result;

以下是我要发布的 json。我在上面的代码中遗漏了什么，我确定这很愚蠢。

   {
      "$type": "BloombergWebAPIMarshal.WebApiDataServiceRequest, BloombergWebAPIMarshal",
      "RequestType": 3,
      "SwapType": 1,
      "SecurityList": [
        {
          "$type": "BloombergWebAPIMarshal.CreditDefaultSwaps, BloombergWebAPIMarshal",
          "ModelNumber": "SP8A1ETA",
          "BrokerSpread": 0
        },
        {
          "$type": "BloombergWebAPIMarshal.CreditDefaultSwaps, BloombergWebAPIMarshal",
          "ModelNumber": "SP3A0TU1",
          "BrokerSpread": 0
        },
        {
          "$type": "BloombergWebAPIMarshal.CreditDefaultSwaps, BloombergWebAPIMarshal",
          "ModelNumber": "SP4A102V",
          "BrokerSpread": 0
        }
      ]
    }

【问题讨论】：

标签： asp.net-mvc-4 asp.net-web-api

【解决方案1】：

创建了另一个重载使用此调用来产生正确的请求：

var response = client.PostAsJsonAsync("processbloombergrequest", oContract, TypeNameHandling.Objects).Result

这是新的重载

public static Task<HttpResponseMessage> PostAsJsonAsync<T>(this HttpClient client, string requestUri, T value, TypeNameHandling typeNameHandling)
{

    return client.PostAsJsonAsync<T>(requestUri, value, CancellationToken.None, typeNameHandling);
}

public static Task<HttpResponseMessage> PostAsJsonAsync<T>(this HttpClient client, string requestUri, T value, CancellationToken cancellationToken, TypeNameHandling typeNameHandling)
{
    var formatter = new JsonMediaTypeFormatter
    {
        SerializerSettings = new JsonSerializerSettings()
        {
            TypeNameHandling = typeNameHandling
        }
    };

    return client.PostAsync<T>(requestUri, value, formatter, cancellationToken);
}

【讨论】：