如何将带有数组的json解析为对象答案

【问题标题】：How to parse json with an array into object如何将带有数组的json解析为对象
【发布时间】：2019-01-21 17:40:14
【问题描述】：

考虑以下 json：

{
  "0": {
    "id": "1",
    "email": "someemail@test.com",
    "tstamp": "2019-01-21 11:19:48",
    "times": "2",
    "tstamp_iso": "2019-01-21T12:19:48-05:00"
  },
  "1": {
    "id": "2",
    "email": "someotheremail@test.com",
    "tstamp": "2019-01-21 11:25:48",
    "times": "2",
    "tstamp_iso": "2019-01-21T12:25:48-05:00"
  },
  "result_code": 1,
  "result_message": "Success!",
  "result_output": "json"
}

我正在尝试将该数据转换为 ac# 对象，但是，我不确定如何处理数组值，因为它的名称为 0、1，而不是嵌套在数组中如果有 20 个结果，它将持续到 20。 我无法更改 json 数据。

我已经走到这一步了：

[JsonObject]
public class FirstObject
{
    [JsonProperty(PropertyName = "id")]
    public string Id { get; set; }

    [JsonProperty(PropertyName = "email")]
    public string Email { get; set; }

    [JsonProperty(PropertyName = "tstamp")]
    public string TimeStamp { get; set; }

    [JsonProperty(PropertyName = "times")]
    public string Times { get; set; }

    [JsonProperty(PropertyName = "tstamp_iso")]
    public string TimeStampIso { get; set; }
}

[JsonObject]
public class SecondObject
{
    public FirstObject[] FirstObjects { get; set; }

    [JsonProperty(PropertyName = "result_code")]
    public string ResultCode { get; set; }

    [JsonProperty(PropertyName = "result_message")]
    public string ResultMessage { get; set; }

    [JsonProperty(PropertyName = "result_output")]
    public string ResultOutput { get; set; }
}

我不明白的是如何将 FirstObjects 映射到 0、1、... 20 的结果。我希望有比写出 20 次并将名称设置为 0 或 1 更好的方法，等等……

【问题讨论】：

标签： c# arrays json

【解决方案1】：

using Newtonsoft.Json;
using Newtonsoft.Json.Linq;
using System;
using System.Collections.Generic;

namespace ConsoleApp2
{
    class Program
    {
        const string json = @"{
                                  ""0"": {
                                    ""id"": ""1"",
                                    ""email"": ""someemail@test.com"",
                                    ""tstamp"": ""2019-01-21 11:19:48"",
                                    ""times"": ""2"",
                                    ""tstamp_iso"": ""2019-01-21T12:19:48-05:00""
                                  },
                                  ""1"": {
                                    ""id"": ""2"",
                                    ""email"": ""someotheremail@test.com"",
                                    ""tstamp"": ""2019-01-21 11:25:48"",
                                    ""times"": ""2"",
                                    ""tstamp_iso"": ""2019-01-21T12:25:48-05:00""
                                  },
                                  ""result_code"": 1,
                                  ""result_message"": ""Success!"",
                                  ""result_output"": ""json""
                              }";

        static void Main(string[] args)
        {
            JObject o = JObject.Parse(json);

            List<FirstObject> l = new List<FirstObject>();

            int c = 0;

            while (o[$"{c}"] != null)
            {
                FirstObject fo = o[$"{c++}"].ToObject<FirstObject>();
                l.Add(fo);
            }

            SecondObject so = JsonConvert.DeserializeObject<SecondObject>(json);

            so.FirstObjects = l.ToArray();

            Console.ReadKey();
        }
    }
}

【讨论】：