无法从 .net 中的 JSON 响应中删除 .d 封装

Question

即使在伟大的博文 Never worry about ASP.NET AJAX’s .d again 之后，我也无法在我的 JSON 响应中逃脱 .d 封装。我不知道我是否做错了什么，所以我将复制我的服务器端和客户端代码。

我正在使用 Newtonsoft.JSON 库对 JSON 进行序列化。

客户端：

<script type="text/javascript">
$(function () {
    $("#bt").click(function () {
        $.ajax({
            type: "POST",
            url: "<%= Page.ResolveUrl("~/MapView.aspx/GetLocations")%>",
            data: "{ type: '<%= Page.RouteData.Values["type"].ToString() %>', id: '<%= Page.RouteData.Values["id"].ToString() %>' }",
            contentType: "application/json; charset=utf-8",
            dataType: "json",
            dataFilter: function(data) {
                var msg;

                if (typeof (JSON) !== 'undefined' && 
                    typeof (JSON.parse) === 'function')
                    msg = JSON.parse(data);
                else
                    msg = eval('(' + data + ')');

                if (msg.hasOwnProperty('d'))
                    return msg.d;
                else
                    return msg;
            },
            success: function (msg) {
                console.log(msg);
            },
        });
    });
});
</script>

服务器端

    [System.Web.Services.WebMethod]
    public static string GetLocations(int id, string type)
    {
        string data = "";


        if (type == "attraction")
        {
            var attractions = db.Attraction
                                .Where(a => a.AttractionId == id)
                                .Select(p => new { p.AttractionId, p.Name, p.Description, p.Location })
                                .ToList();


            JObject attractionsJSON = new JObject(
                new JProperty("Attractions", new JArray(
                    from a in attractions
                    select new JObject(
                        new JProperty("id", a.AttractionId),
                        new JProperty("name", a.Name),
                        new JProperty("location", a.Location),
                        new JProperty("description", a.Description)
                        ))));

            data = attractionsJSON.ToString();
        }
        else if (type == "category")
        {
            var attractions = db.Attraction

                .Select(p => new { p.AttractionId, p.Name, p.Description, p.Location, p.CategoryId })
                .ToList();

            if (id != 0)
            {
                attractions = attractions.Where(a => a.CategoryId == id)
                    .ToList();
            }


            JObject attractionsJSON = new JObject(
                new JProperty("Attractions", new JArray(
                    from a in attractions
                    select new JObject(
                        new JProperty("id", a.AttractionId),
                        new JProperty("name", a.Name),
                        new JProperty("location", a.Location),
                        new JProperty("description", a.Description)
                        ))));

            data = attractionsJSON.ToString();

        }
        return data;
    }

服务器端 - 更新 1

    [System.Web.Services.WebMethod]
    public static void GetLocations(int id, string type)
    {
        string data = "";


        if (type == "attraction")
        {
            var attractions = db.Attraction
                                .Where(a => a.AttractionId == id)
                                .Select(p => new { p.AttractionId, p.Name, p.Description, p.Location })
                                .ToList();


            JArray attractionsJSON = new JArray(
                    from a in attractions
                    select new JObject(
                        new JProperty("id", a.AttractionId),
                        new JProperty("name", a.Name),
                        new JProperty("location", a.Location),
                        new JProperty("description", a.Description)
                        ));

            data = attractionsJSON.ToString();
        }
        else if (type == "category")
        {
            var attractions = db.Attraction

                .Select(p => new { p.AttractionId, p.Name, p.Description, p.Location, p.CategoryId })
                .ToList();

            if (id != 0)
            {
                attractions = attractions.Where(a => a.CategoryId == id)
                    .ToList();
            }


            JArray attractionsJSON = new JArray(
                    from a in attractions
                    select new JObject(
                        new JProperty("id", a.AttractionId),
                        new JProperty("name", a.Name),
                        new JProperty("location", a.Location),
                        new JProperty("description", a.Description)
                        ));

            data = attractionsJSON.ToString();

        }


        var js = new System.Web.Script.Serialization.JavaScriptSerializer();

        HttpContext.Current.Response.Clear();
        HttpContext.Current.Response.ContentType = "application/json; charset=utf-8";
        HttpContext.Current.Response.Write(js.Serialize(data));
        HttpContext.Current.Response.Flush();
        HttpContext.Current.Response.End();
    }
}

Answer 1

尝试使用无返回的 void 方法。而是编写输出以自己响应！

  [System.Web.Services.WebMethod]
    public static void GetLocations(int id, string type)
    {
     // var attractions = something ;

     var js = new System.Web.Script.Serialization.JavaScriptSerializer();

        HttpContext.Current.Response.Clear();
        HttpContext.Current.Response.ContentType = "application/json; charset=utf-8";
        HttpContext.Current.Response.Write(  js.Serialize(attractions )  );
        HttpContext.Current.Response.Flush();
        HttpContext.Current.Response.End();
   }

结束这两个电话非常重要：

flush : 确保将输出写入流

End : 结束流，防止 asp.Net 将空 Json 写入流