脚本因 indexOf 而失败，仅在触发时（不是在测试时）

Question

我在玩 Google Apps 脚本，我快疯了。

点击 Google Apps 脚本站点中的“运行”和“调试”按钮时，以下代码运行良好。 但是，当尝试通过 tyrigger 执行它时，我总是会收到一个奇怪的错误：

TypeError: Fonction indexOf introuvable dans l'objet {year=2020, month=1, day-of-month=8, day-of-week=3, week-of-year=2, hour=17, minute =57，秒=56，时区=UTC，authMode=FULL，triggerUid=2998093}。 在 createIssueReminder(代码:39)

它是法语，但写着function indexOf not found in object {year=2020, month=1, day-of-month=8, day-of-week=3, week-of-year=2, hour=17, minute=57, second=56, timezone=UTC, authMode=FULL, triggerUid=2998093}

这是奇怪的部分：虽然消息与自身一致（好吧，对象不是数组，所以他不能使用 indexOf），它与我的代码完全不一致，因为categories 是一个数组，并且indexOf 被调用。我到底在哪里尝试从日期实例调用 indexOf！？

如前所述，这段代码在 Google Apps 脚本编辑器中完美运行，我不知道在触发器执行时它失败的原因或位置...

对此的任何见解将不胜感激。 谢谢大家。 你是我唯一的希望，欧比旺·克诺比。

/**
 * Check each week if we need a reminder for the week's issue, provided the issue matches the user's chosen categories.
 * @param {string[]} categories The watched categories.
 */
function createIssueReminder(categories) {
  if (!categories)
  {
    categories = ["S", "DD", "D", "M"];
  }
  // Get the "Censored SS Title" spreadsheet
  // cf https://docs.google.com/spreadsheets/d/ss-id-here/
  var spreadsheet = SpreadsheetApp.openById("ss-id-here");

  // Get the sheet storing the issues
  var issueSheet = spreadsheet.getSheetByName("Sorties");

  // Get the range storing the data
  var issueRange = issueSheet.getRange("A2:D81");

  // Get the data from the range
  // use data[row][column] to access values
  var issueData = issueRange.getValues();

  // Get current date and formatted date, in French format Utilities.formatDate(new Date(), "CET", "dd/MM/yy")
  var currentDate = new Date();

  var rowIndex = 0;

  for (rowIndex; rowIndex < issueData.length; rowIndex++)
  { // repeat loop until end of data
    var rowDate = issueData[rowIndex][0];

    // if the date in the cell is today's date...
    if (rowDate.getDate() == currentDate.getDate() && 
        rowDate.getMonth() == currentDate.getMonth() && 
        rowDate.getFullYear() == currentDate.getFullYear())
    { 
      // if the issue's category matches any category set for the user...
      if (categories.indexOf(issueData[rowIndex][3]) != -1)
      {
          // add a reminder with the issue number and content
          createIssueReminderEvent(issueData[rowIndex][3], issueData[rowIndex][1], issueData[rowIndex][2]);
      }
    }
  }  
}

/**
 * Add a reminder to the calendar.
 * @param {number} issueNumber The number of the issue.
 * @param {string} issueMessage The content of the issue.
 */
function createIssueReminderEvent(category, issueNumber, issueMessage) {
  // Prepare the message
  var title = "Issue #"+issueNumber+" ["+category+"]"
  var message = issueMessage;
  var timeZone = "CET";
  var now = new Date();
  var startString = Utilities.formatDate(now, timeZone, 'MMMM dd, yyyy 17:30:00 Z');
  var startTime = new Date(startString);
  var endString = Utilities.formatDate(now, timeZone, 'MMMM dd, yyyy 17:35:00 Z');
  var endTime = new Date(endString); 

  // Create event for the issue
  var event = CalendarApp.getDefaultCalendar().createEvent(title, startTime, endTime, {description: message});

  // Add notification for the event, after deleting default notifications
  event.removeAllReminders();
  event.addPopupReminder(330);

  // Set status (to prevent blocking the day ; workaround as we can't modify transparency of the event)
  // event.addGuest("an-email@goes.here");
  // event.setMyStatus(CalendarApp.GuestStatus.INVITED);

}

Answer 1

您似乎在createIssueReminder 函数上创建了一个触发器。当触发器调用一个函数时，它会传递一个事件对象。见https://developers.google.com/apps-script/guides/triggers/events。

因此，当触发器调用createIssueReminder 时，它会将事件对象作为categories 传递。如果您的代码没有作为参数传递，您的代码只会设置 categories。

在触发器的情况下，它被传递。

把你的函数改成这样：

function createIssueReminder() {
  categories = ["S", "DD", "D", "M"];
...