初始化从 Edit、Paste Special、Paste XML as Classes 获得的 xml 类答案

【问题标题】：Initialize a xml class obtained from Edit, Paste Special, Paste XML as Classes初始化从 Edit、Paste Special、Paste XML as Classes 获得的 xml 类
【发布时间】：2014-07-30 15:25:59
【问题描述】：

我有一个从“编辑、选择性粘贴、将 XML 粘贴为类”生成的类。喜欢解释here. Generating Data Type Classes from XML

XML：

<?xml version="1.0"?>
<Items version="1.0">
  <Item InputFileName="G:\FileFile.txt">
    <Position X="500" Y="100" Z="150"/>
  </Item>
</Items>

类：

namespace Produccion.ClassFile
{
/// <comentarios/>
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true)]
[System.Xml.Serialization.XmlRootAttribute(Namespace = "", IsNullable = false)]
public partial class Items
{

    private ItemsItem[] itemField;

    private decimal versionField;

    /// <comentarios/>
    [System.Xml.Serialization.XmlElementAttribute("Item")]
    public ItemsItem[] Item
    {
        get
        {
            return this.itemField;
        }
        set
        {
            this.itemField = value;
        }
    }

    /// <comentarios/>
    [System.Xml.Serialization.XmlAttributeAttribute()]
    public decimal version
    {
        get
        {
            return this.versionField;
        }
        set
        {
            this.versionField = value;
        }
    }
}

/// <comentarios/>
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true)]
public partial class ItemsItem
{

    private ItemsItemPosition positionField;

    private string inputFileNameField;

    /// <comentarios/>
    public ItemsItemPosition Position
    {
        get
        {
            return this.positionField;
        }
        set
        {
            this.positionField = value;
        }
    }

    /// <comentarios/>
    [System.Xml.Serialization.XmlAttributeAttribute()]
    public string InputFileName
    {
        get
        {
            return this.inputFileNameField;
        }
        set
        {
            this.inputFileNameField = value;
        }
    }
}

/// <comentarios/>
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true)]
public partial class ItemsItemPosition
{

    private decimal xField;

    private decimal yField;

    private decimal zField;

    /// <comentarios/>
    [System.Xml.Serialization.XmlAttributeAttribute()]
    public decimal X
    {
        get
        {
            return this.xField;
        }
        set
        {
            this.xField = value;
        }
    }

    /// <comentarios/>
    [System.Xml.Serialization.XmlAttributeAttribute()]
    public decimal Y
    {
        get
        {
            return this.yField;
        }
        set
        {
            this.yField = value;
        }
    }

    /// <comentarios/>
    [System.Xml.Serialization.XmlAttributeAttribute()]
    public decimal Z
    {
        get
        {
            return this.zField;
        }
        set
        {
            this.zField = value;
        }
    }
}

}

我不知道如何用文件中的数据初始化这个类。

【问题讨论】：

标签： c# asp.net xml visual-studio-2012 visual-studio-2013

【解决方案1】：

反序列化是读取 XML 文档并构造强类型化到文档的 XML Schema (XSD) 的对象的过程。

你会做这样的事情

XmlSerializer serializer = new XmlSerializer(typeof(Items));

// Declare an object variable of the type to be deserialized.
Items i;

using (Stream reader = new FileStream(filename, FileMode.Open))
{
    // Call the Deserialize method to restore the object's state.
    i = (Items)serializer.Deserialize(reader);          
}

【讨论】：