XML 将其解析为一个集合对象答案

【问题标题】：XML parse it into a collection objectXML 将其解析为一个集合对象
【发布时间】：2014-11-19 18:56:00
【问题描述】：

感谢 MikeH，我能够将以下 XML 解析为一个对象。

当我将 XML 文件解析为对象时，它只会将最后一行填充到对象中。我如何将所有行解析为一个集合对象。这些行应该填充到一个集合中。在这种情况下，所有 5 条记录都应该在集合中，而不仅仅是最后一条记录 ()。我花了大部分时间，我一定错过了如何将所有行放入对象中。

  - <ROW>
    <CELL INDEX="0">033331111</CELL> 
    <CELL INDEX="1">Agency 5 LTD</CELL> 
    <CELL INDEX="2">14 Some AVENUE North Brook, FL 65432 3827</CELL> 
    <CELL INDEX="3">A</CELL> 
    <CELL INDEX="4">4412034564</CELL> 
    <CELL INDEX="5" /> 
    <CELL INDEX="6">A - Active</CELL> 
    <CELL INDEX="7">6/1/2008 12:00:00 AM</CELL> 
    </ROW>

使用 Visual Studio 2012 或更高版本：将 XML 复制到剪贴板在 Visual Studio 中：编辑 --> 选择性粘贴 --> 将 XML 粘贴为类然后，您需要将 XML 中的数据序列化到新创建的类中以创建新对象：

var myObject = LoadFromXmlString<DATA_PROVIDERS>(xmlData);

public static T LoadFromXmlString<T>(string xml)
{
  T retval = default(T);
  try
  {
    XmlSerializer s = new XmlSerializer(typeof(T));
    MemoryStream ms = new MemoryStream(ASCIIEncoding.Default.GetBytes(xml));
    retval = (T)s.Deserialize(ms);
    ms.Close(); 
  }
  catch (Exception ex)
  {
    ex.Data.Add("Xml String", xml);
    throw new Exception("Error loading from XML string.  See data.", ex);
  }
  return retval;

}


<?xml version="1.0" encoding="UTF-8" ?> 
-<DATA_PROVIDERS UID="Providers|REP" FORCE_REFRESH="FALSE" DATA_PROVIDER="" FORMATTED="FALSE" REFRESH="TRUE">
 -<DATA_PROVIDER NAME="Prov" SOURCE="Provider" DATE="11/18/2014" DURATION="9s" REFRESH="TRUE" CUBE="1">
  <COLUMN INDEX="0" ID="119" TYPE="String" FORMAT="">Prov ID</COLUMN> 
  <COLUMN INDEX="1" ID="118" TYPE="String" FORMAT="">Prov Name</COLUMN> 
  <COLUMN INDEX="2" ID="113" TYPE="String" FORMAT="">Address Info</COLUMN> 
  <COLUMN INDEX="3" ID="110" TYPE="String" FORMAT="">Enroll Status Code</COLUMN> 
  <COLUMN INDEX="4" ID="119" TYPE="String" FORMAT="">Phone</COLUMN> 
  <COLUMN INDEX="5" ID="110" TYPE="String" FORMAT="">Fax</COLUMN> 
  <COLUMN INDEX="6" ID="109" TYPE="String" FORMAT="">Provider Status</COLUMN> 
  <COLUMN INDEX="7" ID="150" TYPE="Date" FORMAT="m/d/yyyy h:mm:ss am/pm">Provider Start Date</COLUMN> 
  - <ROW>
    <CELL INDEX="0">004042111</CELL> 
    <CELL INDEX="1">CONTOSO West INC</CELL> 
    <CELL INDEX="2">1234 Random Rd. SOMECITY, ZZ 12345 9876</CELL> 
    <CELL INDEX="3">F</CELL> 
    <CELL INDEX="4">5555551234123</CELL> 
    <CELL INDEX="5">5555551234</CELL> 
    <CELL INDEX="6">F - Agency Action</CELL> 
    <CELL INDEX="7">5/31/2011 12:00:00 AM</CELL> 
    </ROW>
  - <ROW>
    <CELL INDEX="0">004011117</CELL> 
    <CELL INDEX="1">CONTOSO North INC</CELL> 
    <CELL INDEX="2">4321 Random Rd. SOMECITY, ZZ 12345 9876</CELL> 
    <CELL INDEX="3">F</CELL> 
    <CELL INDEX="4">5555551234123</CELL> 
    <CELL INDEX="5">5555551234</CELL> 
    <CELL INDEX="6">F - Agency Action</CELL> 
    <CELL INDEX="7">5/31/2011 12:00:00 AM</CELL> 
    </ROW>
  - <ROW>
    <CELL INDEX="0">033337111</CELL> 
    <CELL INDEX="1">Agency 3 INC</CELL> 
    <CELL INDEX="2">200 street 5F Cityabc, NY 12033</CELL> 
    <CELL INDEX="3">A</CELL> 
    <CELL INDEX="4">2128545555</CELL> 
    <CELL INDEX="5" />
    <CELL INDEX="6">A - Active</CELL> 
    <CELL INDEX="7">10/27/2003 12:00:00 AM</CELL> 
    </ROW>
  - <ROW>
    <CELL INDEX="0">033334111</CELL> 
    <CELL INDEX="1">Agency 4 LLC</CELL> 
    <CELL INDEX="2">419 street Town, CT 17033 3945</CELL> 
    <CELL INDEX="3">U</CELL> 
    <CELL INDEX="4" /> 
    <CELL INDEX="5">7172304056</CELL> 
    <CELL INDEX="6">X - Did Not Re-enroll</CELL> 
    <CELL INDEX="7">2/24/2009 12:00:00 AM</CELL> 
    </ROW>
  - <ROW>
    <CELL INDEX="0">033331111</CELL> 
    <CELL INDEX="1">Agency 5 LTD</CELL> 
    <CELL INDEX="2">14 Some AVENUE North Brook, FL 65432 3827</CELL> 
    <CELL INDEX="3">A</CELL> 
    <CELL INDEX="4">4412034564</CELL> 
    <CELL INDEX="5" /> 
    <CELL INDEX="6">A - Active</CELL> 
    <CELL INDEX="7">6/1/2008 12:00:00 AM</CELL> 
    </ROW>
 </DATA_PROVIDER>
</DATA_PROVIDERS>

【问题讨论】：

标签： c# asp.net xml parsing object

【解决方案1】：

您需要做的是使用XmlElement("CELLS") 属性标记您的Cells 集合，以通知XmlSerializer 该集合应序列化为一系列同名元素，而不是具有嵌套子元素的单个元素，像这样：

public class Cell
{
    [XmlText]
    public string Text { get; set; }

    [XmlAttribute("INDEX")]
    public int Index { get; set; }
}

[XmlRoot("ROW")]
public class Row
{
    [XmlElement("CELL")]
    public List<Cell> Cells { get; set; }
}

此外，我注意到您的 Cell 对象包含它们的数组索引作为属性，这似乎是多余的，因为每个单元格在其单元格列表中的位置也传达了此信息。您是否真的希望在您的运行时类中使用该信息——或者您更愿意生成这些信息仅用于序列化？如果您更喜欢后者，您可以将单元格序列化和反序列化为代理数组，其中包含数组索引作为属性属性，如下所示：

public class Cell 
{
    public Cell() {}

    public Cell(Cell other)
    {
        this.Text = other.Text;
    }

    [XmlText]
    public string Text { get; set; }
}

public class XmlCell : Cell // For serialization
{
    public XmlCell() : base() {}

    public XmlCell(Cell other, int index) : base(other)
    {
        this.Index = index;
    }

    [XmlAttribute("INDEX")]
    public int Index { get; set; }
}

[XmlRoot("ROW")]
public class Row
{
    List<Cell> cells;

    [XmlIgnore]
    public List<Cell> Cells
    {
        get
        {
            if (cells == null)
                Interlocked.CompareExchange(ref cells, new List<Cell>(), null);
            return cells;
        }
    }

    [Browsable(false), EditorBrowsable(EditorBrowsableState.Never)]
    [DebuggerBrowsable(DebuggerBrowsableState.Never)]
    [XmlElement("CELL")]
    public XmlCell[] XmlCells // proxy array for serialization.
    {
        get
        {
            var xmlCells = new XmlCell[Cells.Count];
            for (int iCell = 0; iCell < xmlCells.Length; iCell++)
                xmlCells[iCell] = new XmlCell(Cells[iCell], iCell);
            return xmlCells;
        }
        set
        {
            Cells.Clear();
            foreach (var xmlCell in value)
            {
                Cells.EnsureCount(xmlCell.Index + 1);
                Cells[xmlCell.Index] = new Cell(xmlCell);
            }
        }
    }
}

最后是几个扩展方法：

public static class ListExtensions
{
    public static void Resize<T>(this List<T> list, int count)
    {
        if (list == null || count < 0)
            throw new ArgumentException();
        int oldCount = list.Count;
        if (count > oldCount)
        {
            list.Capacity = count;
            for (int i = oldCount; i < count; i++)
                list.Add(default(T));
        }
        else if (count < oldCount)
        {
            for (int i = oldCount - 1; i >= count; i--)
                list.RemoveAt(i);
        }
    }

    public static void EnsureCount<T>(this List<T> list, int count)
    {
        if (list == null || count < 0)
            throw new ArgumentException();
        if (count > list.Count)
            list.Resize(count);
    }
}

【讨论】：