是的……这是可能的。有几种方法可以使用 dapper 解决“一对多”场景:
方法 1 - 返回两个查询,在 DAL 中合并
ALTER PROCEDURE [dbo].[GetCarData]
@CustomerID int,
@Year int
AS
BEGIN
SET NOCOUNT ON;
--return cars
SELECT c.*
from [dbo].Car c
INNER JOIN [dbo].Customer cust ON c.CarID = cust.CarID
WHERE cust.CustID = @CustomerID AND cust.Year = @Year
--return options
SELECT opt.*
from [dbo].Car c
INNER JOIN [dbo].Customer cust ON c.CarID = cust.CarID
INNER JOIN dbo.CarOptions opt ON op.CarID = c.CarID
WHERE cust.CustID = @CustomerID AND cust.Year = @Year
END
DAL
var multi = db.QueryMultiple(getCarDataSp , new { CustomerID = customerId, Year = year },
commandType: CommandType.StoredProcedure));
var cars = multi.Read<CarDTO>();
var options = multi.Read<CarOptionDTO>();
//wire the options to the cars
foreach(var car in cars){
var carOptions = options.Where(w=>w.Car.CarID == car.CarID); //I would override Equals in general so you can write w.Car.Equals(car)...do this on a common DataModel class
car.Options = carOptions.ToList();
}
方法 2 - 返回一个查询,在 DAL 中拆分
过程
ALTER PROCEDURE [dbo].[GetCarData]
@CustomerID int,
@Year int
AS
BEGIN
SET NOCOUNT ON;
SELECT c.*, opt.*
from [dbo].Car c
INNER JOIN [dbo].Customer cust ON c.CarID = cust.CarID
LEFT OUTER JOIN dbo.CarOptions opt ON op.CarID = c.CarID
WHERE cust.CustID = @CustomerID AND cust.Year = @Year
END
DAL
var tuples = db.Query<CarDTO, CarOptionDTO,Tuple<CarDTO,CarOptionDTO>>(getCarDataSp , new { CustomerID = customerId, Year = year },
(car,opt)=> Tuple.Create(car,opt), commandType: CommandType.StoredProcedure);
//group tuples by car
var cars = tuple.GroupBy(gb=>gb.Item1.CarID) //again, overriding equals makes it so you can just to GroupBy(gb=>gb.Item1)
.Select(s=>{
var car = s.First().Item1;
var carOptions = s.Select(t=>t.Item2).ToList()
return car;
});
增强功能
在查询中使用临时表
这会将所有按参数过滤的内容放在一个查询中。后续查询是按 ID 进行的非常简单的选择。
ALTER PROCEDURE [dbo].[GetCarData]
@CustomerID int,
@Year int
AS
BEGIN
SET NOCOUNT ON;
declare @t table(CarID int);
--filter cars (only deal with parameters here)
INSERT INTO @t(CarID)
SELECT c.CarID
FROM dbo.Car c
INNER JOIN [dbo].Customer cust ON c.CarID = cust.CarID
WHERE cust.CustID = @CustomerID AND cust.Year = @Year
--return cars
SELECT c.*
FROM [dbo].Car c
INNER JOIN @t t ON t.CarID = c.CarID
--return options
SELECT opt.*
FROM dbo.CarOptions opt
INNER JOIN @t t ON t.CarID = opt.CarID
END
应用 BaseDTO 来帮助实现平等
一旦您拥有 BaseDTO,并连接您的 ID,您就可以简单地说诸如:cars.Where(w=>w.Equals(car))、dictionary[car](如果它在其中)、if( car.Equals(otherCar)) 或 results.GroupBy(gb=>gb.Car)...
public class BaseDTO
{
internal int ID { get; set; }
/// <summary>
/// If the obj is the same type with the same id we'll consider it equal.
/// </summary>
public override bool Equals(object obj)
{
if(obj == null || this.GetType() != obj.GetType())
{
return false;
}
return this.GetType().GetHashCode() == obj.GetType().GetHashCode() &&
this.ID == (BaseDTO)obj.ID;
}
/// <summary>
/// If you override equals, you should override gethashcode.
/// http://stackoverflow.com/questions/263400/what-is-the-best-algorithm-for-an-overridden-system-object-gethashcode#263416
/// </summary>
public override int GetHashCode()
{
unchecked
{
int hash = 17;
hash = hash * 23 + this.GetType().GetHashCode();
hash = hash * 23 + this.ID;
return hash;
}
}
}
public class CarDTO : BaseDTO
{
public int CarID
{
get { return this.ID; }
set { this.ID = value; }
}
public string Manufacturer { get; set; }
public List<CarOptionDTO> CarOptions { get; set; }
}