如何使用 SIMPLE JSON 将 JSON 反序列化为列表？

Question

我有以下 JSON。

[{"SaveValues":[{"id":1,"allposition":{"x":-4.888263702392578,"y":4.799035549163818},"allrotation":{"x":0.0,"y" :0.0,"z":0.0,"w":1.0},"allscale":{"x":1.0,"y":1.0},"linepos0":{"x":0.0,"y":0.0 ,"z":0.0},"linepos1":{"x":0.0,"y":0.0,"z":0.0},"movetype":1},{"id":2,"allposition": {"x":-4.607616424560547,"y":-4.033360004425049},"allrotation":{"x":0.0,"y":0.0,"z":0.0,"w":1.0},"allscale": {"x":1.0,"y":1.0},"linepos0":{"x":0.0,"y":0.0,"z":0.0},"linepos1":{"x":0.0," y":0.0,"z":0.0},"movetype":1}],"NoteValues":[{"movenumber":1,"notemsg":"ssd"}]},{"SaveValues":[{ "id":1,"allposition":{"x":-4.888263702392578,"y":4.799035549163818},"allrotation":{"x":0.0,"y":0.0,"z":0.0,"w ":1.0},"allscale":{"x":1.0,"y":1.0},"linepos0":{"x":0.0,"y":0.0,"z":0.0},"linepos1" :{"x":0.0,"y":0.0,"z":0.0},"movetype":2},{"id":2,"allposition":{"x":-4.607616424560547,"y" :-4.033360004425049},"allrotation":{"x":0.0,"y":0.0,"z":0.0,"w":1.0},"allscale":{"x":1.0,"y": 1.0},"linepos0":{"x":0.0,"y":0.0,"z":0.0},"linepos1":{"x":0.0,"y":0.0," z":0.0},"movetype":2},{"id":2,"allposition":{"x":4.328777313232422,"y":1.9337825775146485},"allrotation":{"x":0.0," y":0.0,"z":0.0,"w":1.0},"allscale":{"x":1.0,"y":1.0},"linepos0":{"x":0.0,"y" :0.0,"z":0.0},"linepos1":{"x":0.0,"y":0.0,"z":0.0},"movetype":2}],"NoteValues":[{"movenumber ":2,"notemsg":"ddf"}]}]

它们用于序列化的类如下所示。

[System.Serializable]
public class PlayerHandler 
{
    public int id; 
    public Vector2 allposition;
    public Quaternion allrotation;
    public Vector2 allscale;

    public Vector3 linepos0;
    public Vector3 linepos1;
    public int movetype;

    public PlayerHandler(int ids,Vector2 allpos,Quaternion allrot,Vector2 allscal,Vector3 Line0,Vector3 Line1,int Moves)
    {
        this.id = ids;
        this.allposition = allpos;
        this.allrotation = allrot;
        this.allscale = allscal;
        this.linepos0 = Line0;
        this.linepos1 = Line1;
        this.movetype = Moves;
    }

}

[System.Serializable]    
public class PlayerMovement
{
    public int movenumber;
    public string notemsg;

    public PlayerMovement(int Movenum,string Note)
    {
        this.movenumber = Movenum;
        this.notemsg = Note;    
    }
}

在加载方法中我试图反序列化 JSON。所以我创建了一个列表 List<PlayerHandler> SaveValuesDeserialize = new List<PlayerHandler>();

我希望从 Json 中添加 SaveValues。我尝试过的方法如下。

using (FileStream fs = new FileStream(Application.persistentDataPath + "/" + filename, FileMode.Open))
{
    fs.Dispose();
    jsonLoadstring = File.ReadAllText(Path.Combine(Application.persistentDataPath, filename));
    JSONNode JNode = SimpleJSON.JSON.Parse(jsonLoadstring);                

    var deseiralized = JNode[0]["NoteValues"][0]["notemsg"];//Here I am getting the deserialized value for testing.

    //What should I do to get the SaveValues inside the list

    for (int i = 0; i < JNode.Count; i++)
    {
        SaveValuesDeserialize.Add(JNode[i]["SaveValues"][i]);
    }
}

我希望使用简单的 JSON 来解决这个问题。我尝试使用其他方法来反序列化，这有点难以理解。所以选择这种方法来尝试。因为我得到了测试值，我希望我能得到使用 SIMPLEJSON 的值。

Answer 1

反序列化 json 的最简单方法通常是创建对 json 对象建模的类。您可以使用 json2csharp 创建类，或使用 Visual Studio（编辑 -> 选择性粘贴 -> 将 JSON 粘贴为类）。

创建下面的类，然后您可以使用JsonConvert 将 json 反序列化到您的对象中。请注意，由于您只对 SaveValues 感兴趣，因此您不需要映射其他属性（例如 NoteValues）。

反序列化为对象的代码：

var myModel = JsonConvert.DeserializeJson<List<Response>>(json);

// access by iterating through properties
foreach (var item in response)
{
    foreach (var saveValue in item.SaveValues)
    {
        // get all properties of saveValue...
        // saveValue.Allposition;
        // saveValue.Allrotation;
        // saveValue.Allscale;
        // ....
    }
}

这会将json反序列化为List<Response>，其中Response如下：

public class Allposition
{
    public double x { get; set; }
    public double y { get; set; }
}

public class Allrotation
{
    public double x { get; set; }
    public double y { get; set; }
    public double z { get; set; }
    public double w { get; set; }
}

public class Allscale
{
    public double x { get; set; }
    public double y { get; set; }
}

public class Linepos0
{
    public double x { get; set; }
    public double y { get; set; }
    public double z { get; set; }
}

public class Linepos1
{
    public double x { get; set; }
    public double y { get; set; }
    public double z { get; set; }
}

public class SaveValue
{
    public int Id { get; set; }
    public Allposition Allposition { get; set; }
    public Allrotation Allrotation { get; set; }
    public Allscale Allscale { get; set; }
    public Linepos0 Linepos0 { get; set; }
    public Linepos1 Linepos1 { get; set; }
    public int Movetype { get; set; }
}

public class Response
{
    public List<SaveValue> SaveValues { get; set; }
    // NoteValues can safely be removed from model if you don't need the values
    public List<NoteValue> NoteValues { get; set; }
}

// optional
public class NoteValue
{
    public int Movenumber { get; set; }
    public string Notemsg { get; set; }
}

Answer 2

感谢您的回答 haldo 我还没有尝试过您的解决方案，但是我尝试了以下解决方案，它对我有用。我对类进行了一些更改以序列化数据，以便我可以使用它来反序列化它。

public class ListContainer
{

public List<PlayerHandler> SaveValues;
public List<PlayerMovement> NoteValues;


public ListContainer(List<PlayerHandler> _saveVal, List<PlayerMovement> _noteVal)
{
    SaveValues = _saveVal;
    NoteValues = _noteVal;

}

}


[System.Serializable]
public class PlayerHandler 
{
public int id; 
public Vector2 allposition;
public Quaternion allrotation;
public Vector2 allscale;

public Vector3 linepos0;
public Vector3 linepos1;
public int movetype;


public PlayerHandler(int ids,Vector2 allpos,Quaternion allrot,Vector2 allscal,Vector3 Line0,Vector3 Line1,int Moves)

{
    this.id = ids;
    this.allposition = allpos;
    this.allrotation = allrot;
    this.allscale = allscal;
    this.linepos0 = Line0;
    this.linepos1 = Line1;
    this.movetype = Moves;
}


}

[System.Serializable]
public class PlayerMovement
{
public int movenumber;
public string notemsg;

public PlayerMovement(int Movenum,string Note)
{
    this.movenumber = Movenum;
    this.notemsg = Note;

}

}


//Added to retrieve data
[System.Serializable]
public class RootObject
{
    public PlayerHandler[] SaveValues;
    public PlayerMovement[] NoteValues;

    }

//Added to retrieve data
[System.Serializable]
public class RootObjects
{


 public RootObject[] Roots;
}

我对如何检索数据进行了一些更改。

using (FileStream fs = new FileStream(Application.persistentDataPath + "/" + filename, FileMode.Open))
{


fs.Dispose();


jsonLoadstring = File.ReadAllText(Path.Combine(Application.persistentDataPath, filename));


string saveString = "{ \"Roots\" : " + jsonLoadstring + "}";

GetItems = JsonUtility.FromJson<RootObjects>(saveString);
//Loop GetItems to retrieve data.

}