【发布时间】：2016-04-21 07:08:11
【问题描述】：
我的应用程序可用于向单个用户和包含用户集的团队组合发送消息。结构是这样的，一个Message 实体有一个Recipients 实体，而后者又具有一个User 实体列表和一个Team 实体列表。
我正在尝试使用 EF Code First 和 Linq-to-Entities 获取 Message 实体的列表，并且我想包括 Recipients 和 Teams 以避免稍后出现大量延迟加载请求。
奇怪的是，如果我使用 Include 子句，Teams 列表总是空的。经过一番试验，归结为：
var messages = GetAll()
.Include(m => m.Recipients.Teams)
.Where(m => m.Id == 123)
.ToList();
返回一个包含一条消息的列表，其中Teams 列表为空。 （GetAll() 只返回一个IQueryable<Message>。）但是如果我这样做了
var message = GetAll()
.Include(m => m.Recipients.Teams)
.Single(m => m.Id == 123);
然后我收到一条消息，其中 Teams 已正确填充。
任何想法为什么会发生这种情况？
编辑：这是生成的 SQL（取自 Entity Framework Profiler）
Where 语句
SELECT *
FROM (SELECT [Extent1].[Id] AS [Id],
[Extent1].[ParentRelation] AS [ParentRelation],
[Extent1].[CreatedUtc] AS [CreatedUtc],
[Extent1].[Subject] AS [Subject],
[Extent1].[Introduction] AS [Introduction],
[Extent1].[Body] AS [Body],
[Extent1].[GlobalId] AS [GlobalId],
[Extent1].[Team_Id] AS [Team_Id],
[Extent1].[Creator_Id] AS [Creator_Id],
[Extent1].[Parent_Id] AS [Parent_Id],
[Extent1].[ReplyTo_Id] AS [ReplyTo_Id],
[Join1].[Id1] AS [Id1],
[Join1].[ToSupervisors] AS [ToSupervisors],
[Join1].[Organisation_Id] AS [Organisation_Id],
[Join1].[Id2] AS [Id2],
[Join4].[Id3] AS [Id3],
[Join4].[Name] AS [Name],
[Join4].[CreatedUtc] AS [CreatedUtc1],
[Join4].[Description] AS [Description],
[Join4].[Color] AS [Color],
[Join4].[Status] AS [Status],
[Join4].[Organisation_Id] AS [Organisation_Id1],
CASE
WHEN ([Join4].[Recipients_Id1] IS NULL) THEN CAST(NULL AS int)
ELSE 1
END AS [C1]
FROM [dbo].[Messages] AS [Extent1]
INNER JOIN (SELECT [Extent2].[Id] AS [Id1],
[Extent2].[ToSupervisors] AS [ToSupervisors],
[Extent2].[Organisation_Id] AS [Organisation_Id],
[Extent3].[Id] AS [Id2]
FROM [dbo].[Recipients] AS [Extent2]
LEFT OUTER JOIN [dbo].[MessageExtensions] AS [Extent3]
ON [Extent2].[Id] = [Extent3].[Recipients_Id]) AS [Join1]
ON [Extent1].[Recipients_Id] = [Join1].[Id1]
LEFT OUTER JOIN (SELECT [Extent4].[Recipients_Id] AS [Recipients_Id1],
[Extent5].[Id] AS [Id3],
[Extent5].[Name] AS [Name],
[Extent5].[CreatedUtc] AS [CreatedUtc],
[Extent5].[Description] AS [Description],
[Extent5].[Color] AS [Color],
[Extent5].[Status] AS [Status],
[Extent5].[Organisation_Id] AS [Organisation_Id],
[Extent6].[Recipients_Id] AS [Recipients_Id2]
FROM [dbo].[RecipientsTeams] AS [Extent4]
INNER JOIN [dbo].[Teams] AS [Extent5]
ON [Extent4].[Team_Id] = [Extent5].[Id]
INNER JOIN [dbo].[MessageExtensions] AS [Extent6]
ON 1 = 1) AS [Join4]
ON ([Extent1].[Recipients_Id] = [Join4].[Recipients_Id2])
AND ([Extent1].[Recipients_Id] = [Join4].[Recipients_Id1])
WHERE 11021 = [Extent1].[Id]) AS [Project1]
ORDER BY [Project1].[Id] ASC,
[Project1].[Id1] ASC,
[Project1].[Id2] ASC,
[Project1].[C1] ASC
单一陈述
SELECT *
FROM (SELECT [Limit1].[Id1] AS [Id],
[Limit1].[ParentRelation] AS [ParentRelation],
[Limit1].[CreatedUtc] AS [CreatedUtc],
[Limit1].[Subject] AS [Subject],
[Limit1].[Introduction] AS [Introduction],
[Limit1].[Body1] AS [Body],
[Limit1].[GlobalId1] AS [GlobalId],
[Limit1].[Team_Id] AS [Team_Id],
[Limit1].[Creator_Id] AS [Creator_Id],
[Limit1].[Parent_Id] AS [Parent_Id],
[Limit1].[ReplyTo_Id] AS [ReplyTo_Id],
[Limit1].[Id2] AS [Id1],
[Limit1].[ToSupervisors] AS [ToSupervisors],
[Limit1].[Organisation_Id] AS [Organisation_Id],
[Limit1].[Id3] AS [Id2],
[Join5].[Id4] AS [Id3],
[Join5].[Name] AS [Name],
[Join5].[CreatedUtc1] AS [CreatedUtc1],
[Join5].[Description] AS [Description],
[Join5].[Color] AS [Color],
[Join5].[Status] AS [Status],
[Join5].[Organisation_Id] AS [Organisation_Id1],
CASE
WHEN ([Join5].[Recipients_Id1] IS NULL) THEN CAST(NULL AS int)
ELSE 1
END AS [C1]
FROM (SELECT TOP (2) [Extent1].[Id] AS [Id1],
[Extent1].[ParentRelation] AS [ParentRelation],
[Extent1].[CreatedUtc] AS [CreatedUtc],
[Extent1].[Subject] AS [Subject],
[Extent1].[Introduction] AS [Introduction],
[Extent1].[Body] AS [Body1],
[Extent1].[GlobalId] AS [GlobalId1],
[Extent1].[Team_Id] AS [Team_Id],
[Extent1].[Creator_Id] AS [Creator_Id],
[Extent1].[Parent_Id] AS [Parent_Id],
[Extent1].[ReplyTo_Id] AS [ReplyTo_Id],
[Join1].[Id2],
[Join1].[ToSupervisors],
[Join1].[Organisation_Id],
[Join1].[Id3]
FROM [dbo].[Messages] AS [Extent1]
INNER JOIN (SELECT [Extent2].[Id] AS [Id2],
[Extent2].[ToSupervisors] AS [ToSupervisors],
[Extent2].[Organisation_Id] AS [Organisation_Id],
[Extent3].[Id] AS [Id3]
FROM [dbo].[Recipients] AS [Extent2]
LEFT OUTER JOIN [dbo].[MessageExtensions] AS [Extent3]
ON [Extent2].[Id] = [Extent3].[Recipients_Id]) AS [Join1]
ON [Extent1].[Recipients_Id] = [Join1].[Id2]
WHERE 11021 = [Extent1].[Id]) AS [Limit1]
LEFT OUTER JOIN (SELECT [Extent4].[Recipients_Id] AS [Recipients_Id1],
[Extent5].[Id] AS [Id4],
[Extent5].[Name] AS [Name],
[Extent5].[CreatedUtc] AS [CreatedUtc1],
[Extent5].[Description] AS [Description],
[Extent5].[Color] AS [Color],
[Extent5].[Status] AS [Status],
[Extent5].[Organisation_Id] AS [Organisation_Id],
[Join4].[Id5],
[Join4].[Recipients_Id2]
FROM [dbo].[RecipientsTeams] AS [Extent4]
INNER JOIN [dbo].[Teams] AS [Extent5]
ON [Extent4].[Team_Id] = [Extent5].[Id]
INNER JOIN (SELECT [Extent6].[Id] AS [Id5],
[Extent6].[Recipients_Id] AS [Recipients_Id2]
FROM [dbo].[Messages] AS [Extent6]
LEFT OUTER JOIN [dbo].[MessageExtensions] AS [Extent7]
ON [Extent6].[Recipients_Id] = [Extent7].[Recipients_Id]) AS [Join4]
ON [Extent4].[Recipients_Id] = [Join4].[Recipients_Id2]) AS [Join5]
ON [Limit1].[Id1] = [Join5].[Id5]) AS [Project1]
ORDER BY [Project1].[Id] ASC,
[Project1].[Id1] ASC,
[Project1].[Id2] ASC,
[Project1].[C1] ASC
当我手动运行这些查询时，我得到了相同的结果。对于Where，Team 相关属性全部为NULL，而对于Single，它们被填充。
编辑 2GetAll 方法是存储库方法
public virtual IQueryable<T> GetAll()
{
return Context.Set<T>();
}
T 是 Message
【问题讨论】：
-
不可能。你看过进入数据库的 sql 代码吗？
-
GetAll() 方法中的代码是什么？
-
在 SQL 语句和 GetAll 方法中编辑
标签： c# entity-framework linq-to-entities