从 DataGrid 获取单元格值

Question

我有一个 DataGrid，其中填充了来自连接的数据。

private void GetTeamData()
{
    DataContext dc = new DataContext(connString);
    Table<Team> tblLag = dc.GetTable<Team>();
    Table<Division> tblDivision = dc.GetTable<Division>();

    var teams = from team in tblLag
                join division in tblDivision on team.Division equals division.Id
                select new
                {
                    name = team.TeamName,
                    beliggenhet = team.Location,
                    arena = team.Arena,
                    division = division.Name
                };

    dgTeams.ItemsSource = teams;
}

我想从选定的行中获取数据并将其放置在不同的文本框中。经过大量令人沮丧的谷歌搜索和尝试后，我终于找到了一个可行的解决方案：

private void ShowSelectedTeam(Object sender, RoutedEventArgs args)
{
    GetDivisionNames();
    dgTeams.SelectionUnit = DataGridSelectionUnit.FullRow;
    Object selectedTeam = dgTeams.SelectedItem;

    List<PropertyInfo> props = new List<PropertyInfo>(selectedTeam.GetType().GetProperties());

    tbxTeam.Text = props[0].GetValue(selectedTeam, null).ToString();
    tbxBeliggenhet.Text = props[1].GetValue(selectedTeam, null).ToString();
    tbxArena.Text = props[2].GetValue(selectedTeam, null).ToString();
    cbxDivisions.Text = props[3].GetValue(selectedTeam, null).ToString();
}

问题在于，这是一种非常复杂的方法，可以做一些不应该那么困难的事情。对于更简单的代码的建议，我会很高兴。

Answer 1

创建一个包含 name、beliggenhet、arena 和 Division 属性的类型：

public class YourType
{
    public string Name { get; set; }
    public string Beliggenhet { get; set; }
    public string Arena { get; set; }
    public string Division { get; set; }
}

将ItemsSource 设置为IEnumerable<YourType>：

var teams = from team in tblLag
                join division in tblDivision on team.Division equals division.Id
                select new YourType
                {
                    Name = team.TeamName,
                    Beliggenhet = team.Location,
                    Arena = team.Arena,
                    Division = division.Name
                };

并将SelectedItem 属性转换为您的类型：

YourType selectedTeam = dgTeams.SelectedItem as YourType;
if (selectedTeam != null)
{
    tbxTeam.Text = selectedTeam.Name;
    tbxBeliggenhet.Text = selectedTeam.Beliggenhet;
    ...
}

Answer 2

获取选中项属性非常复杂，因为选中项具有匿名类型。

创建一个类型

public class TeamViewModel
{
    public string name { get; set; }
    public string beliggenhet { get; set; }
    public string arena { get; set; }
    public string division { get; set; }
}

在填充 ItemsSource 时创建该类型的对象：

var teams = from team in tblLag
            join division in tblDivision on team.Division equals division.Id
            select new TeamViewModel
            {
                name = team.TeamName,
                beliggenhet = team.Location,
                arena = team.Arena,
                division = division.Name
            };

您将能够将 SelectedItem 转换为具体类型并读取属性而无需反射：

private void ShowSelectedTeam(Object sender, RoutedEventArgs args)
{
    GetDivisionNames();
    dgTeams.SelectionUnit = DataGridSelectionUnit.FullRow;
    var selectedTeam = dgTeams.SelectedItem as TeamViewModel;

    if (selectedTeam == null) return;

    tbxTeam.Text = selectedTeam.name;
    tbxBeliggenhet.Text = selectedTeam.beliggenhet;
    tbxArena.Text = selectedTeam.arena;
    cbxDivisions.Text = selectedTeam.division;
}

---

如果您仍想继续使用匿名类型，可以使用dynamic 类型读取值（仅ShowSelectedTeam 方法更改）：

private void ShowSelectedTeam(Object sender, RoutedEventArgs args)
{
    GetDivisionNames();
    dgTeams.SelectionUnit = DataGridSelectionUnit.FullRow;
    dynamic selectedTeam = dgTeams.SelectedItem;

    if (selectedTeam == null) return;

    tbxTeam.Text = selectedTeam.name.ToString();
    tbxBeliggenhet.Text = selectedTeam.beliggenhet.ToString();
    tbxArena.Text = selectedTeam.arena.ToString();
    cbxDivisions.Text = selectedTeam.division.ToString();
}