【问题标题】:Joining multiple tables in big query在大查询中连接多个表
【发布时间】:2018-12-26 09:47:43
【问题描述】:

我想在 BigQuery 中加入多个表,但 Joining multiple tables in bigquery 的解决方案并没有帮助我获得所需的输出。

我的出发点如下。我正在创建 5 个单独的表格,这些表格显示特定页面可能的每个评级值。在此处查看示例输出:

raw tables

表的创建方式如下:

#standardSQL
  CREATE TEMPORARY FUNCTION tables_in_range(suffix STRING) AS (suffix BETWEEN (
    SELECT
      FORMAT_DATE('%y%m%d',
        DATE('2018-06-01')))
    AND (
    SELECT
      FORMAT_DATE('%y%m%d',
        DATE('2018-06-30'))));

SELECT
  h.page.pagePath AS page,
  Count(h.eventInfo.eventLabel)as five_star
FROM
  `table.ga_sessions_20*` AS t,
  t.hits AS h
WHERE
  h.eventInfo.eventAction='rating'
  AND h.eventInfo.eventLabel ='5'
  AND tables_in_range(_TABLE_SUFFIX)
  AND REGEXP_CONTAINS(h.page.pagePath,
    r'/xyz/')
  AND h.type='EVENT'
group by 1

当按照此处Joining multiple tables in bigquery 的描述加入表格时,我很遗憾没有得到预期的结果。 相反,联接只查看所有 5 个表共有的页面 - 这意味着这些页面在 1-5 的五个可能值中的每一个中都有一个评级。请参阅下面的示例输出。 joint table results

select
five_star.page as page,
five_star.five_star as five_star,
four_star.four_star as four_star,
three_star.three_star as three_star,
two_star.two_star as two_star,
one_star.one_star as one_star
from five_star
join four_star using (page)
join three_star using (page)
join two_star using (page)
JOIN one_star using (page)

我想通过我的联接实现的是这样的表: desired output。 我看到的问题是,如果一个页面没有收到某个评级,它将不会加入查询 atm。不幸的是,我无法通过 Union all、Cross Join 或 left join 找到解决方案,因此非常感谢这里的任何支持!

【问题讨论】:

  • 尝试左外连接。列出所有页面的表将位于连接表达式的左侧。然后使用 IsNull 将空值转换为零。大量的教程和示例在线。一个例子在这里:stackoverflow.com/questions/1664266/…
  • 感谢您将这篇文章转发给我!

标签: sql google-bigquery bigquery-standard-sql


【解决方案1】:

您的查询中的问题:您只是添加到那些具有 5 星评级的事件页面。这就是推荐 full outer join 的原因 - 它向最左边的表添加新行。

我认为在您的情况下,解决方案要容易得多,根本不需要连接,因为所有数据都在同一个表中。 这个是平的和非枢轴的:

#standardSQL
  CREATE TEMPORARY FUNCTION tables_in_range(suffix STRING) AS (suffix BETWEEN '20180601' AND '20180630');

SELECT
  h.page.pagePath AS page,
  h.eventInfo.eventLabel stars,
  COUNT(1) as events
FROM
  `project.dataset.ga_sessions_*` AS t, t.hits AS h
WHERE
  h.eventInfo.eventAction='rating'
  AND h.eventInfo.eventLabel between '1' and '5'
  AND tables_in_range(_TABLE_SUFFIX)
  AND REGEXP_CONTAINS(h.page.pagePath,
    r'/xyz/')
  AND h.type='EVENT'
GROUP BY 1, 2

如果你真的需要类似枢轴的列,它看起来像这样:

#standardSQL
  CREATE TEMPORARY FUNCTION tables_in_range(suffix STRING) AS (suffix BETWEEN '20180601' AND '20180630');

SELECT
  h.page.pagePath AS page,
  SUM( IF(h.eventInfo.eventLabel = '1', 1, 0) ) as oneStarEvents,
  SUM( IF(h.eventInfo.eventLabel = '2', 1, 0) ) as twoStarEvents,
  SUM( IF(h.eventInfo.eventLabel = '3', 1, 0) ) as threeStarEvents,
  SUM( IF(h.eventInfo.eventLabel = '4', 1, 0) ) as fourStarEvents,
  SUM( IF(h.eventInfo.eventLabel = '5', 1, 0) ) as fiveStarEvents
FROM
  `project.dataset.ga_sessions_*` AS t, t.hits AS h
WHERE
  h.eventInfo.eventAction='rating'
  AND h.eventInfo.eventLabel between '1' and '5'
  AND tables_in_range(_TABLE_SUFFIX)
  AND REGEXP_CONTAINS(h.page.pagePath,
    r'/xyz/')
  AND h.type='EVENT'
GROUP BY 1

你也可以COUNT(IF(condition,1,NULL))代替SUM(IF(condition,1,0))

hth!

【讨论】:

    【解决方案2】:

    以下是 BigQuery 标准 SQL

    #standardSQL
    SELECT 
      page,
      SUM(five_star_rating) five_star_rating,
      SUM(four_star_rating) four_star_rating,
      SUM(three_star_rating) three_star_rating,
      SUM(two_star_rating) two_star_rating,
      SUM(one_star_rating) one_star_rating
    FROM (
      SELECT page, 0 one_star_rating, 0 two_star_rating, 0 three_star_rating, 0 four_star_rating, five_star_rating FROM `project.dataset.table5` UNION ALL
      SELECT page, 0, 0, 0, four_star_rating, 0 FROM `project.dataset.table4` UNION ALL
      SELECT page, 0, 0, three_star_rating, 0, 0 FROM `project.dataset.table3` UNION ALL
      SELECT page, 0, two_star_rating, 0, 0, 0 FROM `project.dataset.table2` UNION ALL
      SELECT page, one_star_rating, 0, 0, 0, 0 FROM `project.dataset.table1` 
    )
    GROUP BY page
    

    您可以使用您问题中的虚拟数据进行测试,如下所示

    #standardSQL
    WITH `project.dataset.table5` AS (
      SELECT 'A' page, 1 five_star_rating UNION ALL
      SELECT 'B', 1 UNION ALL
      SELECT 'C', 1 
    ), `project.dataset.table4` AS (
      SELECT 'C' page, 1 four_star_rating UNION ALL
      SELECT 'D', 1 UNION ALL
      SELECT 'F', 1 
    ), `project.dataset.table3` AS (
      SELECT 'F' page, 1 three_star_rating UNION ALL
      SELECT 'G', 1 UNION ALL
      SELECT 'H', 1 
    ), `project.dataset.table2` AS (
      SELECT 'H' page, 1 two_star_rating UNION ALL
      SELECT 'I', 1 UNION ALL
      SELECT 'J', 1 
    ), `project.dataset.table1` AS (
      SELECT 'J' page, 1 one_star_rating UNION ALL
      SELECT 'K', 1 UNION ALL
      SELECT 'L', 1 
    )
    SELECT 
      page,
      SUM(five_star_rating) five_star_rating,
      SUM(four_star_rating) four_star_rating,
      SUM(three_star_rating) three_star_rating,
      SUM(two_star_rating) two_star_rating,
      SUM(one_star_rating) one_star_rating
    FROM (
      SELECT page, 0 one_star_rating, 0 two_star_rating, 0 three_star_rating, 0 four_star_rating, five_star_rating FROM `project.dataset.table5` UNION ALL
      SELECT page, 0, 0, 0, four_star_rating, 0 FROM `project.dataset.table4` UNION ALL
      SELECT page, 0, 0, three_star_rating, 0, 0 FROM `project.dataset.table3` UNION ALL
      SELECT page, 0, two_star_rating, 0, 0, 0 FROM `project.dataset.table2` UNION ALL
      SELECT page, one_star_rating, 0, 0, 0, 0 FROM `project.dataset.table1` 
    )
    GROUP BY page
    

    【讨论】:

      【解决方案3】:

      不幸的是,我无法通过 Union all、Cross Join 或 left join 找到解决方案......

      另一种选择是使用 FULL JOIN,如下例所示

      #standardSQL
      SELECT
        COALESCE(five_star.page, four_star.page, three_star.page, two_star.page, one_star.page) AS page,
        IFNULL(five_star.five_star_rating, 0) AS five_star,
        IFNULL(four_star.four_star_rating, 0) AS four_star,
        IFNULL(three_star.three_star_rating, 0) AS three_star,
        IFNULL(two_star.two_star_rating, 0) AS two_star,
        IFNULL(one_star.one_star_rating, 0) AS one_star
      FROM `project.dataset.table5` five_star
      FULL JOIN `project.dataset.table4` four_star USING (page)
      FULL JOIN `project.dataset.table3` three_star USING (page)
      FULL JOIN `project.dataset.table2` two_star USING (page)
      FULL JOIN `project.dataset.table1` one_star USING (page)
      

      您可以使用您问题中的虚拟数据进行测试,如下所示

      #standardSQL
      WITH `project.dataset.table5` AS (
        SELECT 'A' page, 1 five_star_rating UNION ALL
        SELECT 'B', 1 UNION ALL
        SELECT 'C', 1 
      ), `project.dataset.table4` AS (
        SELECT 'C' page, 1 four_star_rating UNION ALL
        SELECT 'D', 1 UNION ALL
        SELECT 'F', 1 
      ), `project.dataset.table3` AS (
        SELECT 'F' page, 1 three_star_rating UNION ALL
        SELECT 'G', 1 UNION ALL
        SELECT 'H', 1 
      ), `project.dataset.table2` AS (
        SELECT 'H' page, 1 two_star_rating UNION ALL
        SELECT 'I', 1 UNION ALL
        SELECT 'J', 1 
      ), `project.dataset.table1` AS (
        SELECT 'J' page, 1 one_star_rating UNION ALL
        SELECT 'K', 1 UNION ALL
        SELECT 'L', 1 
      )
      SELECT
        COALESCE(five_star.page, four_star.page, three_star.page, two_star.page, one_star.page) AS page,
        IFNULL(five_star.five_star_rating, 0) AS five_star,
        IFNULL(four_star.four_star_rating, 0) AS four_star,
        IFNULL(three_star.three_star_rating, 0) AS three_star,
        IFNULL(two_star.two_star_rating, 0) AS two_star,
        IFNULL(one_star.one_star_rating, 0) AS one_star
      FROM `project.dataset.table5` five_star
      FULL JOIN `project.dataset.table4` four_star USING (page)
      FULL JOIN `project.dataset.table3` three_star USING (page)
      FULL JOIN `project.dataset.table2` two_star USING (page)
      FULL JOIN `project.dataset.table1` one_star USING (page)   
      

      结果符合预期:

      Row page    five_star   four_star   three_star  two_star    one_star     
      1   A       1           0           0           0           1    
      2   B       1           0           0           0           1    
      3   C       1           1           0           0           1    
      4   D       0           1           0           0           0    
      5   F       0           1           1           0           0    
      6   G       0           0           1           0           0    
      7   H       0           0           1           1           0    
      8   I       0           0           0           1           0    
      9   J       0           0           0           1           0    
      

      【讨论】:

      • 亲爱的米哈伊尔,非常感谢您的回复。我刚刚尝试了使用 FULL JOIN 的解决方案,并且效果很好!我也将使用 subselect / UNION ALL 尝试您的示例,但到目前为止,这正是我正在寻找的表。谢谢!
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