具有嵌套 JSON 的 POST 请求正文的构造函数的 POJO 类答案

【问题标题】：POJO class with Constructor for the POST request body which has nested JSON具有嵌套 JSON 的 POST 请求正文的构造函数的 POJO 类
【发布时间】：2021-03-03 07:09:12
【问题描述】：

我想为嵌套了 JSON 的 POST 请求主体创建一个带有构造函数的 POJO 类，但我不知道如何在其中调用 JSONArray？

PS：我不想用setter方法设置数据，我想用Constructor来设置数据。

这是 JSON：

{
"FirstName": "test",
"LastName": "account",
"PASSWORD": "Password123*",
"Email": [
    {
        "TYPE": "Primary",
        "VALUE": "arpitay6@mail7.io"
    }


]}

我创建的 POJO -


import java.util.List;

public class PostAccountCreateAPI {

    private List <Email> email;
    private String password;
    private String firstname;
    private String lastname;
    
    public PostAccountCreateAPI(List<Email> email, String password, String firstname, String lastname) {
        
        this.email = email;
        this.password = password;
        this.firstname = firstname;
        this.lastname = lastname;
    }

    public String getFirstname() {
        return firstname;
    }

    public void setFirstname(String firstname) {
        this.firstname = firstname;
    }

    public String getLastname() {
        return lastname;
    }

    public void setLastname(String lastname) {
        this.lastname = lastname;
    }

    public String getPassword() {
        return password;
    }

    public void setPassword(String password) {
        this.password = password;
    }

    public List<Email> getEmail() {
        return email;
    }

    public void setEmail(List<Email> email) {
        this.email = email;
    }

}



package pojo;

public class Email {

    private String type;
    private String value;
    
    

    public Email(String type, String value) {
        
        this.type = type;
        this.value = value;
    }


    public String getType() {
        return type;
    }

    public void setType(String type) {
        this.type = type;
    }

    public String getValue() {
        return value;
    }

    public void setValue(String value) {
        this.value = value;
    }

}

在 main 方法中，我使用 - 调用 POJO

PostAccountCreateAPI PostAccountCreateAPIPayLoad = new PostAccountCreateAPI("pri@mail7.io", "P@$$w0rd", "arpita", "garg");

但它不起作用。谁能建议如何做到这一点？

【问题讨论】：

在什么情况下它不起作用？你得到什么错误？

标签： java json cucumber bdd pojo

【解决方案1】：

好的....这里我给出一个完整的例子：

PostAccountCreateApi 类：

import java.util.List;

public class PostAccountCreateAPI{

    private String FirstName;
    private String LastName;
    private String PASSWORD;
    private List<Email> Email;


    public PostAccountCreateAPI(){}

    public PostAccountCreateAPI(String FirstName, String LastName, String PASSWORD, List<Email> Email){

        this.FirstName = FirstName;

        this.LastName = LastName;

        this.PASSWORD = PASSWORD;

        this.Email = Email;

    }

    public void setFirstName(String FirstName){

        this.FirstName = FirstName;

    }

    public String getFirstName(){

        return this.FirstName;

    }

    public void setLastName(String LastName){

        this.LastName = LastName;

    }

    public String getLastName(){

        return this.LastName;

    }

    public void setPASSWORD(String PASSWORD){

        this.PASSWORD = PASSWORD;

    }

    public String getPASSWORD(){

        return this.PASSWORD;

    }

    public void setEmail(List<Email> Email){

        this.Email = Email;

    }
    public List<Email> getEmail(){

        return this.Email;

    }

}

电子邮件类：

public class Email {

    String TYPE;
    String VALUE;

    public Email() {
    }

    public Email(String TYPE, String VALUE) {

        this.TYPE = TYPE;

        this.VALUE = VALUE;

    }

    public void setTYPE(String TYPE) {

        this.TYPE = TYPE;

    }

    public String getTYPE() {

        return this.TYPE;

    }

    public void setVALUE(String VALUE) {

        this.VALUE = VALUE;

    }

    public String getVALUE() {

        return this.VALUE;
    }
}

具有虚拟主方法的主类：


import java.util.ArrayList;
import java.util.List;

public class Main {
    public static void main(String[] args) {

        List<Email> emailList = new ArrayList<>();

        emailList.add(new Email("Primary", "pri@mail7.io"));
        emailList.add(new Email("Primary", "amimulahsan7@gmail.com"));

        //And list goes on......


        PostAccountCreateAPI postAccountCreateAPI = new PostAccountCreateAPI("arpita", "garg",
                "P@$$w0rd", emailList);
    }
}

【讨论】：

感谢您的回复。但我不知道如何在 main 方法中调用这个 PostAccountCreateAPI。我们如何将参数作为 List 传递？
@ArpitaGarg 我现在提供了一个功能齐全的示例作为答案。如果有帮助，请采纳答案。

【解决方案2】：

构造函数的第一个参数是List<Email>，但您当前将String 作为第一个参数传递给构造函数。创建Email 对象列表，然后调用PostAccountCreateAPI 构造函数。

【讨论】：