转动长度为 X -> 长度 Y [重复] 的字符串

Question

我在变量 x 和 y 中有两个字符串，其中 x 的长度大于 y 的长度。如何将较小的字符串 (y) 映射到大字符串 (x) 的大小？

例如：

x = "appleappleapple" # (length 15)
y = "abc" # (length 3) This should be mapped to "abcabcabcabcabc"

while len(y) < len(x):
    y+=y
while len(y) > len(x):
    y = y[:-1] 

print x 
print y 

appleappleapple
abcabcabcabcabc

有没有一种非常pythonic/有效的方法来做这个操作？

Answer 1

x = "appleappleapple" # (length 15)
y = "abc" # (length 3) This should be mapped to "abcabcabcabcabc"
z = (y*(len(x)/len(y)+1))[:len(x)]