表单传递选择到下一页

Question

我有一个从我的数据库中获取数据的选择器。

当我选择一项并按下Add to list时，它会生成一个表格：

这一切的代码是：

    <!--Selector-->
    <?php

// Get name and id data from the db. In an assoc array

$results = $database->Selector();
echo "<form name='form' method='POST' id='selector'>";
echo "<select name='train_name' id='train_name' multiple='multiple'>";

// Loop trough the results and make an option of every train_name

foreach($results as $res) {
    echo "<option value=" . $res['train_name'] . ">" . $res['train_name'] . "</option>";
}

echo "</select>";
echo "<br />" . "<td>" . "<input type='submit' name='Add' value='Add to list'/>" . "</td>";
echo "</form>";

if (isset($_POST["train_name"])) {

    // Get all data from database, in an assoc array

    $results = $database->getAllAssoc();

    // Make table headers

?>
            <div id="train_select_table">
            <form name="selector" method="post" action="customer_list.php?user_id=<?php
    echo $_SESSION['user_id'] ?>">
                <table>
                    <tr>
                        <th>Train name</th>
                        <th>Number of bogies</th>
                        <th>Number of axles</th>
                        <th>Delete</th>
                        <th>More info</th>
                        <th>Check</th>
                    <!--Only for admins (later!)-->
                    <!--<th>XML</th>
                        <th>SQL</th>    -->
                    </tr>
                <div id="looprow">
                    <?php
    foreach($results as $res) {

        // Loop trough results, generate a tablerow every time

?>
                    <tr>     
                        <td name="train_name"><?php
        echo $res['train_name'] ?></td>
                        <td><?php
        echo $res['number_of_bogies'] ?></td>
                        <td><?php
        echo $res['number_of_axles'] ?></td>
                        <td><a href="remove_from_table.php?train_id=<?php
        echo $res['train_id'] ?>">Delete</a></td>
                        <td><a href="expand_info.php?train_id=<?php
        echo $res['train_id'] ?>">More Information</a></td> 
                        <td><input type="checkbox" name="checkbox" value="<?php
        echo $res['train_id'] ?>"></td>
                                                    <!--Only for admins (later!)--> 
                        <!--<td><a href="convert_to_xml.php?train_id=<?php
        echo $res['train_id'] ?>">XML</a></td>
                        <td><a href="convert_to_sql.php?train_id=<?php
        echo $res['train_id'] ?>">SQL</a></td>-->
                    </tr>
                <?php
    }

?>
                </div>
            </table><br />
            <input name="Add to list" type="submit" id="add_to_list" value="add_to_list">
        </form>
        </div>
        <?php
}

?>

Functions:

    function getAllAssoc() {
            $sql = "SELECT * FROM train_information WHERE train_name = :train_name";
            $sth = $this->pdo->prepare($sql);
            $sth->bindParam(":train_name", $_POST["train_name"]);
            $sth->execute();
            return $sth->fetchAll();
        }
    
    function selector() {
            $sql = "SELECT train_name, train_id FROM train_information";
            $sth = $this->pdo->prepare($sql);   
            $sth->execute();
            return $sth->fetchAll();
        }

当我检查检查按钮时，然后按 Add to list 。你会去customer_list.php。在此页面上，我想显示所选项目的信息。我现在拥有的是：

<?php
    echo $_POST["checkbox"];
?>

这向我显示了一个数字（当我选择了一个项目时），它是火车/项目的 ID。

但是如何显示选中复选框的所有信息呢？ 此外，如果我在表中有多列火车，例如 10 列。我只选择 7 列并按下按钮。我希望下一页 customer_list.php 显示这 7 个特定结果。

Answer 1

两件事：

1.改变

echo "<select name='train_name' id='train_name' multiple='multiple'>";

到

echo "<select name='train_name[]' id='train_name' multiple='multiple'>";

2.改变

function getAllAssoc() {
        $sql = "SELECT * FROM train_information WHERE train_name = :train_name";
        $sth = $this->pdo->prepare($sql);
        $sth->bindParam(":train_name", $_POST["train_name"]);
        $sth->execute();
        return $sth->fetchAll();
    }

到

function getAllAssoc() {
        $sql = "SELECT * FROM train_information WHERE train_name IN(:train_name)";
        $sth = $this->pdo->prepare($sql);
        $sth->bindParam(":train_name", implode(",",$_POST["train_name"]));
        $sth->execute();
        return $sth->fetchAll();
    }

只是调整查询中的引号，因为我没有测试过这段代码，感觉单引号会有问题。

上面所做的是，我们已经在一个数组中获取输入，并根据这个数组输入相应地获取结果。

希望你能明白！

Answer 2

您需要将复选框代码编辑为：

<td><input type="checkbox" name="checkbox[]" value="<?php echo $res['train_id']?>"></td>

customer_list.php 代码：

<?php

function getAllAssoc_id($id) {
        $sql = "SELECT * FROM train_information WHERE id = :id";
        $sth = $this->pdo->prepare($sql);
        $sth->bindParam(":id", $id);
        $sth->execute();
        return $sth->fetchAll();
    }

    //echo $_POST["checkbox"];

    echo"<table><tr><td>Train Name</td><td>Train Id</td></tr>";
    foreach($_POST["checkbox"] as $key=>$val){
    $data=getAllAssoc_id($val);
    echo"<tr><td>".$data['train_name']."</td><td>".$data['id']."</td></tr>";

    }
    echo"</table";
?>

Answer 3

您必须将您的复选框名称作为一个数组，即name="checkbox[]"，因此在操作页面上您将获得一个ID 数组。现在您只需使用 mysql "IN" 子句查询选定的 train_id。

我可以告诉你一个查询

Select * from table where train_id IN(array you got from check boxes)