如何将 Dictionary<string,List<Custom Type>> 序列化为 XML

Question

我有一个自定义类：

public class DicExpense
{
    [XmlElement]
    public string EmployeeName { get; set; }

    [XmlElement]
    public string Company { get; set; }        
}

我将其放入这样的字典中：

  var dict = new Dictionary<string, List<DicExpense>>();
  dict.Add("Expense1",new List<DicExpense>())
  dict["Expense1"].Add(new DicExpense() {EmployeeName = "Sam", Comment = "something"})
  dict["Expense1"].Add(new DicExpense() {EmployeeName = "Sam", Comment = "something"})


  dict.Add("Expense2",new List<DicExpense>())
  dict["Expense2"].Add(new DicExpense() {EmployeeName = "John", Comment = "something"})
  dict["Expense2"].Add(new DicExpense() {EmployeeName = "John", Comment = "something"})

我想将其序列化为 XML：

 <Expense>
 <key>Expense1</key>
 <EmployeeName>Sam</EmployeeName>
 <Comment>something</Comment>
 <EmployeeName>John</EmployeeName>
 <Comment>something</Comment>
 </Expense>

我正在尝试这个：

 StringBuilder output = new StringBuilder();
 var writer = new StringWriter(output);

 XmlSerializer serializer = new XmlSerializer(typeof(Dictionary<string,     List<DicExpense>>));
 serializer.Serialize(writer, records);
 Console.WriteLine(output);

但它不起作用。当您的值是自定义类型的集合时，有没有办法序列化它？

Answer 1

如果要序列化/反序列化使用 Dictionary<TKey, TValue> 的类型，请使用 DataContractSerializer：

 [DataContract(Name = "Expense")]
 public class DicExpense
 {       
    [DataMember]
    public string EmployeeName { get; set; }

    [DataMember(Order = 0)]
    public string Company { get; set; }
  }

 var dict = new Dictionary<string, List<DicExpense>>();
 dict.Add("Expense1", new List<DicExpense>());
 dict["Expense1"].AddRange(new List<DicExpense>
 {
    new  DicExpense()
    {
        EmployeeName = "Sam",
        Company = "company1"
    },
    new DicExpense()
    {
        EmployeeName = "John",
        Company = "company1"
    }
 });

 dict.Add("Expense2", new List<DicExpense>());
 dict["Expense2"].AddRange(new List<DicExpense>
 {
     new DicExpense()
     {
         EmployeeName = "Smith",
         Company = "company2"
      },
      new DicExpense()
      {
         EmployeeName = "John",
         Company = "company2"
      }
 });

 var serializer = new DataContractSerializer(typeof(Dictionary<string, List<DicExpense>>));
 using (var writer = XmlWriter.Create(Console.Out))
 {
      serializer.WriteObject(writer, dict);
 }