Symfony 2：错误：从控制器调用非对象上的成员函数 has()

Question

这是我的控制器 A：

<?php

namespace MonitoringBundle\Controller;

use Symfony\Bundle\FrameworkBundle\Controller\Controller;
use Symfony\Component\HttpFoundation\Response;
use Sensio\Bundle\FrameworkExtraBundle\Configuration\Route;
use Sensio\Bundle\FrameworkExtraBundle\Configuration\Template;

use Doctrine\ORM\Query\ResultSetMapping;

use MonitoringBundle\Entity\MarketplaceShop;

use MonitoringBundle\Controller\BController;

class AController extends Controller
{
    /**
     * @Route("/A")
     * @Template()
     */
    public function AAction()
    {
        $B = new BController;

        $response = $B->BAction();

        return $this->render('MonitoringBundle:Default:index.html.twig', array('BVar' => $response));
    }
}
?>

那是控制器 B：

<?php

namespace MonitoringBundle\Controller;

use Symfony\Bundle\FrameworkBundle\Controller\Controller;
use Symfony\Component\HttpFoundation\Response;
use Sensio\Bundle\FrameworkExtraBundle\Configuration\Route;
use Sensio\Bundle\FrameworkExtraBundle\Configuration\Template;

use Doctrine\ORM\Query\ResultSetMapping;

use MonitoringBundle\Entity\MarketplaceShop;

class BController extends Controller
{
    /**
     * @Route("/B")
     * @Template()
     */
    public function BAction()
    {

        $id     = 'A2WPX7PK44TEBQ';
        $em     = $this->getDoctrine()->getManager();
        $shop   = $em->getRepository('MonitoringBundle:MarketplaceShop')
                     ->findOneByUniqueShopId($id);
        if (!$shop) {
            // do something
            return new Response('Shop does not exist.');
        } else {
            // do something else
            return new Response('Shop exists!');
        }
    }

}
?>

当我拨打http://example.com/B 时，一切都很好，我得到了回复：

商店不存在。

但是当我调用http://example.com/A 时，我得到一个错误：

错误：在非对象上调用成员函数 has() 500 内部服务器错误 - FatalErrorException

堆栈跟踪： 在 vendor/symfony/symfony/src/Symfony/Bundle/FrameworkBundle/Controller/Controller.php 第 291 行

public function getDoctrine()
{
if (!$this->container->has('doctrine')) {
throw new \LogicException('The DoctrineBundle is not registered in your application.');
}

为什么它适用于 /B/ 而不适用于 /A/？

Answer 1

一种解决方法是将你的B控制器声明为服务，并在A控制器中通过$this->container->get('controllerB');调用它

在 services.yml 中：

controllerB:
    class: MonitoringBundle\Controller\BController
    arguments:
        entity_manager: "@doctrine.orm.entity_manager"


class AController extends Controller
{
    /**
     * @Route("/A")
     * @Template()
     */
    public function AAction()
    {
        $B = $this->container->get('BController');

        $response = $B->BAction();

        return $this->render('MonitoringBundle:Default:index.html.twig', array('BVar' => $response));
    }
}


class BController extends Controller {
    /**
     * @var EntityManager
     */
    protected $entityManager;

    /**
     * Constructor
     * @param $entityManager
     */
    public function __construct($entityManager)
    {
        $this->entityManager = $entityManager;
    }

    /**
     * @Route("/B")
     * @Template()
     */
    public function BAction()
    {

        $id     = 'A2WPX7PK44TEBQ';
        $shop   = $this->entityManager->getRepository('MonitoringBundle:MarketplaceShop')
                     ->findOneByUniqueShopId($id);
        if (!$shop) {
            // do something
            return new Response('Shop does not exist.');
        } else {
            // do something else
            return new Response('Shop exists!');
        }
    }
}

Answer 2

除了@Christian Bujoreau 的回答，你还可以使用转发方法：http://symfony.com/doc/current/book/controller.html#forwarding-to-another-controller

public function AAction()
{
    $response = $this->forward('MonitoringBundle:BController:BAction', array(
        // 'some_variable'  => $some_variable,
    ));

...

return $response;

}