【发布时间】:2017-11-29 23:47:42
【问题描述】:
所以我从 w3schools 学到了这一点。 . .然而,该示例使用直接注入代码的数据。我想知道如何使用相同的代码块而不是从表单接收数据
<?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "myDBPDO";
try {
$conn = new PDO("mysql:host=$servername;dbname=$dbname", $username,
$password);
// set the PDO error mode to exception
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
// prepare sql and bind parameters
$stmt = $conn->prepare("INSERT INTO MyGuests (firstname, lastname,
email)
VALUES (:firstname, :lastname, :email)");
$stmt->bindParam(':firstname', $firstname);
$stmt->bindParam(':lastname', $lastname);
$stmt->bindParam(':email', $email);
// insert a row
$firstname = "John";
$lastname = "Doe";
$email = "john@example.com";
$stmt->execute();
// insert another row
$firstname = "Mary";
$lastname = "Moe";
$email = "mary@example.com";
$stmt->execute();
// insert another row
$firstname = "Julie";
$lastname = "Dooley";
$email = "julie@example.com";
$stmt->execute();
echo "New records created successfully";
}
catch(PDOException $e)
{
echo "Error: " . $e->getMessage();
}
$conn = null;
?>
【问题讨论】:
-
把
"John"换成表单值,可能是$_POST['firstname']? -
@chris85 谢谢!短而甜
标签: php mysql forms pdo prepared-statement