【问题标题】:Getting location data from an image (Instagram/JS)从图像中获取位置数据 (Instagram/JS)
【发布时间】:2013-05-12 23:11:52
【问题描述】:

我一直在做一个附带项目,但遇到了障碍。我可以通过标签搜索并显示他们的图片结果,但我还想在每张图片下方放置详细信息,特别是位置信息。我在 Javascript 中执行此操作,并注释掉了我认为需要调整的行,但是删除了注释标记,甚至图片都没有显示。有小费吗?调用 Instagram 打印的 JSON 对象返回以下数据:

Object
  - data: Array[20]
    - 0: Object
      + caption: Object
      + comments: Object
        created_time: "1334402906"
        filter: "Nashville"
        id: "169306311223447303_5913362"
      - images: Object
        + low_resolution: Object
        - standard_resolution: Object
          height: 612
          url: "http://distilleryimage7.instagram.com/f3f8d7b2862411e19dc71231380fe523_7.jpg"
          width: 612
        + thumbnail: Object
        + likes: Object
          link: "http://instagr.am/p/JZfzFqtI8H/"
          location: Object
          tags: Array[1]
          type: "image"
          user: Object

我的代码如下所示:

// Instantiate an empty object.
var Instagram = {};

// Small object for holding important configuration data.
Instagram.Config = {
  clientID: 'xxxxxxxxxxxxxxxxxxxxxxxxxxxxx',
  apiHost: 'https://api.instagram.com'
};


// ************************
// ** Main Application Code
// ************************
(function(){
  var photoTemplate, resource;

  function init(){
    bindEventHandlers();
    photoTemplate = _.template($('#photo-template').html());
  }

  function toTemplate(photo){
    photo = {
      count: photo.likes.count,
      avatar: photo.user.profile_picture,
      photo: photo.images.low_resolution.url,
      url: photo.link
      //location: photo.location  <--------------------------This line.
    };

    return photoTemplate(photo);
  }

  function toScreen(photos){
    var photos_html = '';
    //var photos_location = ''; <------------------------This line.

    $('.paginate a').attr('data-max-tag-id', photos.pagination.next_max_id)
                    .fadeIn();

    $.each(photos.data, function(index, photo){
      photos_html += toTemplate(photo);
      //photos_location += toTemplate(photo); <-----------------This line.
    });

    $('div#photos-wrap').append(photos_html);
    //$('div#photos-wrap').append(photos_location) <------------------This line. 
  }


  function generateResource(tag){
    var config = Instagram.Config, url;

    if(typeof tag === 'undefined'){
      throw new Error("Resource requires a tag. Try searching for cherry blossoms.");
    } else {
      // Make sure tag is a string, trim any trailing/leading whitespace and take only the first
      // word, if there are multiple.
      tag = String(tag).trim().split(" ")[0];
    }

    // Configures the URL to search for pictures that fit the tag description.
    url = config.apiHost + "/v1/tags/" + tag + "/media/recent?callback=?&client_id=" + config.clientID;

    return function(max_id){
      var next_page;
      if(typeof max_id === 'string' && max_id.trim() !== '') {
        next_page = url + "&max_id=" + max_id;
      }
      return next_page || url;
    };
  }

  function paginate(max_id){
    $.getJSON(generateUrl(tag), toScreen);
  }

  function search(tag){
    resource = generateResource(tag);
    $('.paginate a').hide();
    $('#photos-wrap *').remove();
    fetchPhotos();
  }

  function fetchPhotos(max_id){
    $.getJSON(resource(max_id), toScreen);
  }

  function bindEventHandlers(){
    $('body').on('click', '.paginate a.btn', function(){
      var tagID = $(this).attr('data-max-tag-id');
      fetchPhotos(tagID);
      return false;
    });

    // Bind an event handler to the `submit` event on the form
    $('form').on('submit', function(e){

      // Stop the form from fulfilling its destinty.
      e.preventDefault();

      // Extract the value of the search input text field.
      var tag = $('input.search-tag').val().trim();

      // Invoke `search`, passing `tag` (unless tag is an empty string).
      if(tag) {
        search(tag);
      };

    });

  }

  function showPhoto(p){
    $(p).fadeIn();
  }

  // Public API
  Instagram.App = {
    search: search,
    showPhoto: showPhoto,
    init: init
  };
}());


$(function(){
  Instagram.App.init();

  Instagram.App.search('takoyaki');
});

【问题讨论】:

  • 你的代码有 jsfiddle 吗?您是否在控制台中查看过您遇到了什么错误?
  • jsfiddle.net/FNM7G/1 - 虽然我在某个地方搞砸了。不记得这个网站对我来说是什么,很高兴你提到它。谢谢!我不完全确定这些错误。
  • 我其实只是想在这个网站上扩展:grammy.eduvoyage.com 功能是一样的,但我想从每张图片中提取更多信息。在某个时候,我也想获取这些位置 ID,并将它们显示在图像下方的 Google 地图上。
  • 所以你使用的是jquery和下划线?我没有看到您的 jsfiddle 中包含任何一个?
  • 我应该提一下,我对这一切都很陌生,只是按照教程来完成这一切 ^^;本教程:eduvoyage.com/instagram-search-app.html

标签: javascript loops location instagram geotagging


【解决方案1】:

这行得通,只要照片有位置数据,不是所有的都可以

CSS

body {
  background: #e3e8ec url(http://grammy.eduvoyage.com/images/tile.png) repeat 50% 0;
}
#search {
  height: 40px;
  padding: 10px;
  text-align: center;
  position: fixed;
  width: 240px;
  margin: 0 auto;
  z-index: 100;
  left: 50%;
  top: 0;
  margin-left: -130px;
  border-radius:0 0 5px 5px;
}

.search-wrap {
  background: white;
  line-height: 30px;
  height: 30px;
  text-align: left;
  border-radius: 3px;
  width: 230px;
  margin: 0;
  border: 1px solid #ddd;
}

#photos-wrap {
  width: 810px;
  margin: 70px auto 40px auto;
  position: relative;
  z-index: 1;
}

.photo .avatar {
  width: 40px;
  height: 40px;
  padding: 2px;
  position: absolute;
  bottom: 11px;
  right: 8px;
  background: white;
}

.photo  {
  margin-bottom: 20px;
  float: left;
  position: relative;
  width: 250px;
  height: 250px;
  border-radius: 5px;
  background: white;
  padding: 5px;
  margin: 5px;
  box-shadow: 0 0 5px rgba(0, 0, 0, 0.3);
}

.photo .heart {
  height: 16px;
  position: absolute;
  left: 13px;
  bottom: 16px;
  padding: 0 5px 0 22px;
  font-size: 12px;
  font-weight: bold;
  line-height: 16px;
  border-radius: 2px;
  border: 1px solid #ddd;
  background: white url('http://grammy.eduvoyage.com/images/fav.png') no-repeat 2px 0;
}

.paginate {
  display: block;
  clear: both;
  margin: 10px;
  text-align: center;
  margin: 0 auto;
  padding: 20px 0;
  height: 100px;
}

.location {
    position: relative;
    top: -48px;
    left: 7px;
    border-style: solid;
    border-width: 1px;
    border-radius: 3px;
    background-color: white;
}

HTML

      <div id='photos-wrap'>
      </div>

      <div class='paginate'>
        <a class='btn'  style='display:none;' data-max-tag-id='' href='#'>View More...</a>
      </div>
    </div>
  </div>
</div>

<script type="text/template" id="photo-template">
  <div class='photo'>
    <a href='<%= url %>' target='_blank'>
      <img class='main' src='<%= photo %>' width='250' height='250' style='display:none;' onload='Instagram.App.showPhoto(this);'/>
    </a>
    <img class='avatar' width='40' height='40' src='<%= avatar %>' />
    <span class='heart'><strong><%= count %></strong></span>
    <span class='location'><%= longitude %> <%= latitude %></span>
  </div>
</script>

Javascript

// Instantiate an empty object.
var Instagram = {};

// Small object for holding important configuration data.
Instagram.Config = {
  clientID: '4895197dfce340cb9004101ce6ae9215',
  apiHost: 'https://api.instagram.com'
};


// ************************
// ** Main Application Code
// ************************
(function(){
  var photoTemplate, resource;

  function init(){
    bindEventHandlers();
    photoTemplate = _.template($('#photo-template').html());
  }

  function toTemplate(photo){
    photo = {
      count: photo.likes.count,
      avatar: photo.user.profile_picture,
      photo: photo.images.low_resolution.url,
      url: photo.link,
      longitude: photo.location && photo.location.longitude,
      latitude: photo.location && photo.location.latitude
    };

    return photoTemplate(photo);
  }

  function toScreen(photos){
    var photos_html = '';

    $('.paginate a').attr('data-max-tag-id', photos.pagination.next_max_id)
                    .fadeIn();

    $.each(photos.data, function(index, photo){
      photos_html += toTemplate(photo);
    });

    $('div#photos-wrap').append(photos_html);
  }

  function generateResource(tag){
    var config = Instagram.Config, url;

    if(typeof tag === 'undefined'){
      throw new Error("Resource requires a tag. Try searching for cats.");
    } else {
      // Make sure tag is a string, trim any trailing/leading whitespace and take only the first 
      // word, if there are multiple.
      tag = String(tag).trim().split(" ")[0];
    }

    url = config.apiHost + "/v1/tags/" + tag + "/media/recent?callback=?&client_id=" + config.clientID;

    return function(max_id){
      var next_page;
      if(typeof max_id === 'string' && max_id.trim() !== '') {
        next_page = url + "&max_id=" + max_id;
      }
      return next_page || url;
    };
  }

  function paginate(max_id){    
    $.getJSON(generateUrl(tag), toScreen);
  }

  function search(tag){
    resource = generateResource(tag);
    $('.paginate a').hide();
    $('#photos-wrap *').remove();
    fetchPhotos();
  }

  function fetchPhotos(max_id){
    $.getJSON(resource(max_id), toScreen);
  }

  function bindEventHandlers(){
    $('body').on('click', '.paginate a.btn', function(){
      var tagID = $(this).attr('data-max-tag-id');
      fetchPhotos(tagID);
      return false;
    });

    // Bind an event handler to the `submit` event on the form
    $('form').on('submit', function(e){

      // Stop the form from fulfilling its destinty.
      e.preventDefault();

      // Extract the value of the search input text field.
      var tag = $('input.search-tag').val().trim();

      // Invoke `search`, passing `tag` (unless tag is an empty string).
      if(tag) {
        search(tag);
      };

    });

  }

  function showPhoto(p){
    $(p).fadeIn();
  }

  // Public API
  Instagram.App = {
    search: search,
    showPhoto: showPhoto,
    init: init
  };
}());

$(function(){
  Instagram.App.init();

  // Start with a search on cats; we all love cats.
  Instagram.App.search('cats');  
});

开启jsfiddle

【讨论】:

  • 我在 PHP 中看到了一种过滤结果以仅显示带有位置元素的图片的方法;这也可以在 JS 中完成吗?最终,我想获取位置信息并将其显示在谷歌地图上,以便您可以在地图上查看坐标。
  • 我猜你可以用 Javascript 过滤客户端,我不明白为什么不能。
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