【问题标题】:Android-Java HTTPCLIENT send http parameters with Content-Disposition image uploadingAndroid-Java HTTPCLIENT 通过 Content-Disposition 图片上传发送 http 参数
【发布时间】:2020-04-03 23:38:07
【问题描述】:

我在 java 中有一个使用 HttpClient 的图像上传器功能,我正在使用 Content-Disposition。 但是我被困在那里我没有意识到如何在这个帖子请求中插入另一个身体形式参数。 例如我想添加一个参数,如:

description = "my image's description"

我的代码:

File file = new File(filepath);
        FileInputStream fileInputStream = new FileInputStream(file);
        URL url = new URL(UPLOAD_SERVER);
        connection = (HttpURLConnection) url.openConnection();
        connection.setDoInput(true);
        connection.setDoOutput(true);
        connection.setUseCaches(false);
        connection.setRequestMethod("POST");
        connection.setRequestProperty("Connection", "Keep-Alive");
        connection.setRequestProperty("User-Agent", "Android Multipart HTTP Client 1.0");
        connection.setRequestProperty("Content-Type", "multipart/form-data; boundary="+boundary);
        outputStream = new DataOutputStream(connection.getOutputStream());
        outputStream.writeBytes("--" + boundary + "\r\n");
        outputStream.writeBytes("Content-Disposition: form-data; name=\"" + "img_upload" + "\"; filename=\"" + q[idx] +"\"" + "\r\n");
        outputStream.writeBytes("Content-Type: image/jpeg" + "\r\n");
        outputStream.writeBytes("Content-Transfer-Encoding: binary" + "\r\n");
        outputStream.writeBytes("\r\n");
        bytesAvailable = fileInputStream.available();
        bufferSize = Math.min(bytesAvailable, 1048576);
        buffer = new byte[bufferSize];
        bytesRead = fileInputStream.read(buffer, 0, bufferSize);
        while(bytesRead > 0) {
            outputStream.write(buffer, 0, bufferSize);
            bytesAvailable = fileInputStream.available();
            bufferSize = Math.min(bytesAvailable, 1048576);
            bytesRead = fileInputStream.read(buffer, 0, bufferSize);
        }
        outputStream.writeBytes("\r\n");
        outputStream.writeBytes("--" + boundary + "--" + "\r\n");
        inputStream = connection.getInputStream();
        int status = connection.getResponseCode();
        if (status == HttpURLConnection.HTTP_OK) {
            BufferedReader in = new BufferedReader(new InputStreamReader(connection.getInputStream()));
            String inputLine;
            StringBuffer response = new StringBuffer();
            while ((inputLine = in.readLine()) != null) {
                response.append(inputLine);
            }
            inputStream.close();
            connection.disconnect();
            fileInputStream.close();
            outputStream.flush();
            outputStream.close();
            return response.toString();
        } else {
            throw new Exception("Non ok response returned");
        }

【问题讨论】:

    标签: java php android httpclient


    【解决方案1】:

    我会尝试这样做:

    outputStream.writeBytes("--" + boundary + "\r\n");
    outputStream.writeBytes("Content-Disposition: form-data; name=\"" + "img_upload" + "\"; filename=\"" + q[idx] +"\"" + "\r\n");
    outputStream.writeBytes("Content-Type: image/jpeg" + "\r\n");
    outputStream.writeBytes("Content-Transfer-Encoding: binary" + "\r\n");
    outputStream.writeBytes("--" + boundary + "\r\n");
    outputStream.writeBytes("Content-Disposition: form-data; name=\"" + "description" + "\"" + "\r\n");
    outputStream.writeBytes("\r\n");
    outputStream.writeBytes(description);
    outputStream.writeBytes("--" + boundary + "\r\n");
    

    【讨论】:

    • 不幸。不工作。但是描述变量应该在 outputStream.writeBytes(description);
    • @HalitKalayci 它是问题开头的字符串:description = "my image's description"
    • 感谢您的帮助卢卡斯,它的工作原理。我拼错了一些东西,我设法修复了它。再次感谢。
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