使用 Underscore JS 对 JSON 数组进行分组

Question

我有一个 JSON 数组对象如下：

var orders = [{
    orderId: 1,
    firstName: 'John',
    lastName: 'Smith',
    address: {
        street: '123 Main Street',
        city: 'New York',
        zip: 10001
    }
}, {
    orderId: 2,
    firstName: 'John',
    lastName: 'Smith',
    address: {
        street: '456 Main Street',
        city: 'New York',
        zip: 10001
    }
}, {
    orderId: 3,
    firstName: 'John',
    lastName: 'Smith',
    address: {
        street: '123 Main Street',
        city: 'New York',
        zip: 10001
    }
}, {
    orderId: 4,
    firstName: 'John',
    lastName: 'Smith',
    address: {
        street: '123 Main Street',
        city: 'New York',
        zip: 10002
    }
}];

我正在尝试使用underscore.js创建一个新的数组对象，按地址分组以满足显示所有已发货到123 Main Street, New York, 1001的订单的用例。

underscore.js 是正确的做法吗？如果是这样，我应该怎么做？任何提示都会有所帮助。

Answer 1

见_.groupBy

console.log(_.groupBy(orders, function(obj){
    return obj.address.street + '|' + obj.address.city + '|' + obj.address.zip;
}));

见http://jsfiddle.net/mendesjuan/gc47ruyL/1/

此示例假定地址中不能包含|，您可能需要更好的分隔符，或使用JSON.stringify：

console.log(_.groupBy(orders, function(obj){
    return JSON.stringify([obj.address.street, obj.address.city, obj.address.zip]);
}));

Answer 2

如果你的页面中已经有下划线，你可以使用

var filteredOrders = _.filter(orders, function(order){
  return (order.address.street === '123 Main Street') &&
          (order.address.city === 'New York') &&
          (order.address.zip === 10001);
});

Fiddle