我假设您正在使用 api 调用来获取用于显示文件列表或单个文件的初始数据。您必须这样做才能将 id 传递回 PUT 方法以更新文件。
以下是 GET 方法的示例:
[HttpGet]
public IEnumerable<FileMetaData> Get()
{
var allFiles = MyEntities.Files.Select(f => new FileMetaData()
{
Name = f.Name,
FileName = f.FileName,
Description = f.Description,
FileId = f.Id,
ContentType = f.ContentType,
Tags = f.Tags,
NumberOfKB = f.NumberOfKB
});
return allFiles;
}
这是 POST 方法的示例,您可以将其改为 PUT(更新):
[HttpPost]
[ValidateMimeMultipartContentFilter]
public async Task<IHttpActionResult> PutFile()
{
try
{
var streamProvider =
await Request.Content.ReadAsMultipartAsync(new InMemoryMultipartFormDataStreamProvider());
//We only allow one file
var thisFile = files[0];
//For a PUT version, you would grab the file from the database based on the id included in the form data, instead of creating a new file
var file = new File()
{
FileName = thisFile.FileName,
ContentType = thisFile.ContentType,
NumberOfKB = thisFile.ContentLength
};
//This is the file metadata that your client would pass in as formData on the PUT / POST.
var formData = streamProvider.FormData;
if (formData != null && formData.Count > 0)
{
file.Id = formData["id"];
file.Description = formData["description"];
file.Name = formData["name"] ?? string.Empty;
file.Tags = formData["tags"];
}
file.Resource = thisFile.Data;
//For your PUT, change this to an update.
MyEntities.Entry(file).State = EntityState.Detached;
MyEntities.Files.Add(file);
await MyEntities.SaveChangesAsync();
//return the ID
return Ok(file.Id.ToString());
}
我从这篇文章中得到了 InMemoryMultipartFormDataStreamProvider:
https://conficient.wordpress.com/2013/07/22/async-file-uploads-with-mvc-webapi-and-bootstrap/
并对其进行了调整以适应我返回的表单数据的需求。