如何调用异步函数而不期待它们的返回？答案

【问题标题】：How to call asynchronous functions without expecting returns from them?如何调用异步函数而不期待它们的返回？
【发布时间】：2019-05-18 14:18:54
【问题描述】：

在下面的代码中，我想调用 task1 和 task2 但不期待这些方法的返回，这可能吗？

import asyncio
async def say(something, delay):
  await asyncio.sleep(delay)
  print(something)

loop = asyncio.get_event_loop()
task1 = loop.create_task(say('hi', 1))
task2 = loop.create_task(say('hoi', 2))
loop.run_until_complete(asyncio.gather(task1, task2))

我想在一个while循环中处理一个队列中的一些东西，而不是等待，因为我不需要返回函数，例如伪代码：

import asyncio
async def say(something, delay):
  await asyncio.sleep(delay)
  print(something)

def main():
    while True:
        # search for database news
        # call say asynchronous, but I do not need any return, I just want you to do anything, independent
        time.sleep(1)

【问题讨论】：

标签： python-3.x asynchronous parallel-processing wait python-asyncio

【解决方案1】：

如果我对您的理解正确，您希望在创建任务时已经拥有。创建的任务将被执行"in background"：你不必等待它。

import asyncio


async def say(something, delay):
  await asyncio.sleep(delay)
  print(something)


async def main():
    # run tasks without awaiting for their results
    for i in range(5):
        asyncio.create_task(say(i, i))

    # do something while tasks running "in background"
    while True:
        print('Do something different')
        await asyncio.sleep(1)


asyncio.run(main())

结果：

Do something different
0
Do something different
1
2
Do something different
3
Do something different
4
Do something different
Do something different
Do something different
Do something different

【讨论】：