将 Excel 导入 DataGridView答案

【问题标题】：Importing Excel into DataGridView将 Excel 导入 DataGridView
【发布时间】：2012-07-05 17:23:08
【问题描述】：

我正在制作一个将两个数据库合并在一起的程序....我可以使用以下代码将 excel 电子表格导入 DataGridView：

     string connectionString = @"Provider=Microsoft.Jet.OLEDB.4.0;Data Source=C:\test.xls;Extended Properties=""Excel 8.0;HDR=YES;IMEX=1""";

                DbProviderFactory factory = DbProviderFactories.GetFactory("System.Data.OleDb");

                DbDataAdapter adapter = factory.CreateDataAdapter();

                DbCommand selectCommand = factory.CreateCommand();
                selectCommand.CommandText = "SELECT * FROM [All Carpets to Excel$]";

                DbConnection connection = factory.CreateConnection();
                connection.ConnectionString = connectionString;

                selectCommand.Connection = connection;

                adapter.SelectCommand = selectCommand;

                data = new DataSet();

                adapter.Fill(data);

                dataGridView1.DataSource = data.Tables[0].DefaultView;

我遇到的问题是我试图找到一种方法将源文件更改为对话框返回的路径。我有一个包含文件路径的字符串文件。如何将其合并到连接字符串中？

或者也许有更好的方法来做到这一点？

谢谢！

卢克

【问题讨论】：

只需将 Data Source=C:\test.xls" 替换为对话框中的值即可。
@TimLentine 对话框中的值可能会根据文件所在的位置而改变。我需要在运行时进行此更改。
用“连接字符串”中的对话框路径更改字符串名称的路径会引发错误。

标签： c# excel datagridview dialog connection-string

【解决方案1】：

使用OleDbConnectionStringBuilder 类修改您的连接字符串。

string fileName = "your path to the excel.xls"; // From the dialog box.

OleDbConnectionStringBuilder connStringBuilder =
    new OleDbConnectionStringBuilder();

connStringBuilder.DataSource = fileName;  // Set path to excel file
connStringBuilder.Provider = "Microsoft.Jet.OLEDB.4.0";
connStringBuilder.Add("Extended Properties", "Excel 8.0;HDR=YES;IMEX1");        

...

// Get the connection string from the builder.
connection.ConnectionString = connStringBuilder.ConnectionString;

【讨论】：

【解决方案2】：

您只需要 Microsoft.Office.Interop.Excel 并将其与数据表和数据集结合起来。

    Excel.Workbook ExWorkbook;
    Excel.Worksheet ExWorksheet;
    Excel.Range ExRange;
    Excel.Application ExObj = new Excel.Application();

    DataTable dt = new DataTable("dataTable");
    DataSet dsSource = new DataSet("dataSet");
    dt.Reset();

    openFileDialog1.Filter = "Excel Files|*.xls;*.xlsx;*.xlsm";
    DialogResult result = openFileDialog1.ShowDialog();

    if (result == DialogResult.OK) // Test result.
    {
        ExWorkbook = ExObj.Workbooks.Open(openFileDialog1.FileName, Missing.Value, Missing.Value, Missing.Value, Missing.Value, Missing.Value, Missing.Value, Missing.Value, Missing.Value, Missing.Value, Missing.Value, Missing.Value, Missing.Value, Missing.Value, Missing.Value);
        ExWorksheet = (Excel.Worksheet)ExWorkbook.Sheets.get_Item(1);
        ExRange = ExWorksheet.UsedRange;

        for (int Cnum = 1; Cnum <= ExRange.Columns.Count; Cnum++)
        {
            dt.Columns.Add(new DataColumn((ExRange.Cells[1, Cnum] as Excel.Range).Value2.ToString()));
        }
        dt.AcceptChanges();

        string[] columnNames = new String[dt.Columns.Count];
        for (int i = 0; i < dt.Columns.Count; i++)
        {
            columnNames[0] = dt.Columns[i].ColumnName;
        }

        for (int Rnum = 2; Rnum <= ExRange.Rows.Count; Rnum++)
        {
            DataRow dr = dt.NewRow();
            for (int Cnum = 1; Cnum <= ExRange.Columns.Count; Cnum++)
            {
                if ((ExRange.Cells[Rnum, Cnum] as Excel.Range).Value2 != null)
                {
                    dr[Cnum - 1] = (ExRange.Cells[Rnum, Cnum] as Excel.Range).Value2.ToString();
                }
            }
            dt.Rows.Add(dr);
            dt.AcceptChanges();
        }
        ExWorkbook.Close(true, Missing.Value, Missing.Value);
        ExObj.Quit();

        dataGridView1.DataSource = dt;

【讨论】：