如何根据 NSDate 计算年龄答案

【问题标题】：How to calculate the age based on NSDate如何根据 NSDate 计算年龄
【发布时间】：2011-05-26 17:17:42
【问题描述】：

如何根据出生日期计算年龄，格式为 6/24/1976 星期一/日期/年...

【问题讨论】：

我们不介意帮助人们做作业，但我们希望他们承认这就是事实。我们希望他们在自己解决问题方面表现出某种努力。
我想基本算法会类似于age = current_date - birth_date。
出生日期必须是d/m/y格式吗？
你为什么不按照你认为应该做的方式发布呢？然后，我们将为您提供帮助。

【解决方案1】：

其中许多答案没有正确考虑闰年等，最好使用 Apple 的方法而不是除以常数。

斯威夫特

let birthday: NSDate = ...
let now = Date()
let ageComponents = calendar.dateComponents([.year], from: birthday, to: now)
let age = ageComponents.year

目标-C

NSDate* birthday = ...;

NSDate* now = [NSDate date];
NSDateComponents* ageComponents = [[NSCalendar currentCalendar] 
                                   components:NSCalendarUnitYear 
                                   fromDate:birthday
                                   toDate:now
                                   options:0];
NSInteger age = [ageComponents year];

我认为这比这里的任何其他答案都更清晰、更准确。

编辑

通过将birthday 和now 都设置为中午来提高准确性。这是使用Date 扩展（在 Swift 中）的一种方法...

/// Returns a new date identical to the receiver except set to precisely noon.
/// Example: let now = Date().atNoon()
func atNoon() -> Date {
    var components = (Calendar.current as NSCalendar).components([.day, .month, .year, .era, .calendar, .timeZone], from: self)
    components.hour = 12
    components.minute = 0
    components.second = 0
    components.nanosecond = 0
    return Calendar.current.date(from: components)!
}

【讨论】：

哇！很好的答案！这值得一个自我面对手掌：D！
这帮助我获得了 int 的年龄。在我的情况下，我还必须在使用它之前从字符串转换日期： NSDateFormatter *dateFormat = [[NSDateFormatter alloc] init]; [dateFormat setDateFormat:@"MM/dd/yyyy"]; NSDate *birthday = [dateFormat dateFromString:@"11/19/1986"];
ofc 我必须添加这应该是正确的答案
干得好，自从你回答以来一直在使用它！谢谢！
@MurraySagal 这应该被编辑成答案！ now 和 birthday 同时开始是至关重要的，因为我们人类计算年龄的方式有一个怪癖：这是你的生日整天不管你实际出生的时间在。

【解决方案2】：

以下是根据您的出生日期（以年和日为单位）计算实际年龄的方法：

NSString *birthDate = @"03/31/1990";    
NSDate *todayDate = [NSDate date];
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:@"MM/dd/yyyy"];
int time = [todayDate timeIntervalSinceDate:[dateFormatter dateFromString:birthDate]];
int allDays = (((time/60)/60)/24);
int days = allDays%365;
int years = (allDays-days)/365;

NSLog(@"You live since %i years and %i days",years,days);

它返回年份和确切的日期。如果您需要，您可以更改 NSDateFormatter 等等。

【讨论】：

你住的地方没有闰年吗？ ;)
我住在火星上——只是好奇号还没有发现我。我不熟悉 Objective-C 中日期计算的可能性，但我的答案是一个非常简单的解决方案，但我认为那里有一个更精确的解决方案（在你的星球上）;-)
您将如何使用这种方法计算月份？

【解决方案3】：

这是我从 link.. 得到的代码。它工作得很好。输出将类似于“5 年 6 个月”，所有用例都包含在其中。

- (NSString *)age:(NSDate *)dateOfBirth {
   NSInteger years;
   NSInteger months;
   NSInteger days;

   NSCalendar *calendar = [NSCalendar currentCalendar];
    unsigned unitFlags = NSCalendarUnitYear | NSCalendarUnitMonth | NSCalendarUnitDay;

   NSDateComponents *dateComponentsNow = [calendar components:unitFlags fromDate:[NSDate date]];
   NSDateComponents *dateComponentsBirth = [calendar components:unitFlags fromDate:dateOfBirth];

   if (([dateComponentsNow month] < [dateComponentsBirth month]) ||

(([dateComponentsNow month] == [dateComponentsBirth month]) && ([dateComponentsNow day] < [dateComponentsBirth day]))) {
   years = [dateComponentsNow year] - [dateComponentsBirth year] - 1;
} else {
   years = [dateComponentsNow year] - [dateComponentsBirth year];
}

if ([dateComponentsNow year] == [dateComponentsBirth year]) {
   months = [dateComponentsNow month] - [dateComponentsBirth month];
} else if ([dateComponentsNow year] > [dateComponentsBirth year] && [dateComponentsNow month] > [dateComponentsBirth month]) {
   months = [dateComponentsNow month] - [dateComponentsBirth month];
} else if ([dateComponentsNow year] > [dateComponentsBirth year] && [dateComponentsNow month] < [dateComponentsBirth month]) {
   months = [dateComponentsNow month] - [dateComponentsBirth month] + 12;
} else {
   months = [dateComponentsNow month] - [dateComponentsBirth month];
}

if ([dateComponentsNow year] == [dateComponentsBirth year] && [dateComponentsNow month] == [dateComponentsBirth month]) {
   days = [dateComponentsNow day] - [dateComponentsBirth day];
}

if (years == 0 && months == 0) {
   if (days == 1) {
      return [NSString stringWithFormat:@"%d day", days];
   } else {
      return [NSString stringWithFormat:@"%d days", days];
   }
} else if (years == 0) {
   if (months == 1) {
      return [NSString stringWithFormat:@"%d month", months];
   } else {
      return [NSString stringWithFormat:@"%d months", months];
   }
} else if ((years != 0) && (months == 0)) {
   if (years == 1) {
       return [NSString stringWithFormat:@"%d year", years];
   } else {
       return [NSString stringWithFormat:@"%d years", years];
   }
} else {
  if ((years == 1) && (months == 1)) {
      return [NSString stringWithFormat:@"%d year and %d month", years, months];
  } else if (years == 1) {
      return [NSString stringWithFormat:@"%d year and %d months", years, months];
  } else if (months == 1) {
      return [NSString stringWithFormat:@"%d years and %d month", years, months];
  } else {
      return [NSString stringWithFormat:@"%d years and %d months", years, months];
  }
}
}

如果您希望年龄为 int，请尝试以下答案.. 我从关注 link 得到的

- (NSInteger)age:(NSDate *)dateOfBirth {
  NSCalendar *calendar = [NSCalendar currentCalendar];
  unsigned unitFlags = NSCalendarUnitYear | NSCalendarUnitMonth | NSCalendarUnitDay;
  NSDateComponents *dateComponentsNow = [calendar components:unitFlags fromDate:[NSDate date]];
  NSDateComponents *dateComponentsBirth = [calendar components:unitFlags fromDate:dateOfBirth];

  if (([dateComponentsNow month] < [dateComponentsBirth month]) ||
      (([dateComponentsNow month] == [dateComponentsBirth month]) && ([dateComponentsNow day] < [dateComponentsBirth day]))) {
    return [dateComponentsNow year] - [dateComponentsBirth year] - 1;
  } else {
    return [dateComponentsNow year] - [dateComponentsBirth year];
  }
}

希望这对某人有所帮助..

【讨论】：

这帮助我获得了 int 的年龄。在我的情况下，我还必须在调用函数 NSDateFormatter *dateFormat = [[NSDateFormatter alloc] init]; 之前从字符串转换日期。 [dateFormat setDateFormat:@"MM/dd/yyyy"]; NSDate *dob = [dateFormat dateFromString:@"11/19/1986"]; NSLog(@"AGE:%d",[self age:dob]);
最完整的答案也计算月份，谢谢

【解决方案4】：

如果你想单独查找年龄。使用下面的一个也包括闰年计算

- (NSInteger)age:(NSDate *)dateOfBirth {
    NSCalendar *calendar = [NSCalendar currentCalendar];
    unsigned unitFlags = NSYearCalendarUnit | NSMonthCalendarUnit | NSDayCalendarUnit;
    NSDateComponents *dateComponentsNow = [calendar components:unitFlags fromDate:[NSDate date]];
    NSDateComponents *dateComponentsBirth = [calendar components:unitFlags fromDate:dateOfBirth];

    if (([dateComponentsNow month] < [dateComponentsBirth month]) ||
        (([dateComponentsNow month] == [dateComponentsBirth month]) && ([dateComponentsNow day] < [dateComponentsBirth day]))) {
        return [dateComponentsNow year] - [dateComponentsBirth year] - 1;
    } else {
        return [dateComponentsNow year] - [dateComponentsBirth year];
    }
}

【讨论】：

【解决方案5】：

一个简单易用的快速扩展来获取年龄/多大是NSDate

extension NSDate {
    var age: Int {
        let calendar: NSCalendar = NSCalendar.currentCalendar()
        let now = calendar.startOfDayForDate(NSDate())
        let birthdate = calendar.startOfDayForDate(self)
        let components = calendar.components(.Year, fromDate: birthdate, toDate: now, options: [])
        return components.year
    }
}

示例：

NSDate(timeIntervalSince1970:0).age // => 45 (as of nov 2015) Epoch happened 45 year ago !

顺便说一句，你要小心，这是西方的年龄概念，其他一些国家的计算方式不同（例如Korea）。

【讨论】：

【解决方案6】：

可能我错了，但这更简单，不是吗？

NSTimeInterval ageInterval = [birthDate timeIntervalSinceDate:[NSDate date]];

NSInteger age = ABS(ageInterval / (60 * 60 * 24 * 365));

【讨论】：

如果是闰年怎么办？
比较简单，不准确:-)

【解决方案7】：

基于cobbal's solution的Swift 3+语法中的方法。

func calculateAgeInYearsFromDateOfBirth (birthday: Date) -> Int {
        let now = Date()
        let calendar = Calendar.current

        let ageComponents = calendar.dateComponents([.year], from: birthday, to: now)
        let age = ageComponents.year!
        return age
    }

【讨论】：

【解决方案8】：

最简单的方法是使用 NSCalendar：

NSDate *_dateOfBirth = ...;
NSDateComponent *_diff = [[NSCalendar currentCalendar] components:NSYearCalendarUnit | NSMonthCalendarUnit | NSDayCalendarUnit fromDate:_dateOfBirth toDate:[NSDate date] options:0];

NSLog(@"%@", _diff);

【讨论】：

【解决方案9】：

   -(NSInteger) ComputeYearMonth
    {
  NSDateFormatter *format = [[NSDateFormatter alloc] init];
[format setDateFormat:@"yyyy-MM-dd"];

NSDate *DateOfBirth=[format dateFromString:[NSString stringWithFormat:@"%@-%@-%@",year,month,day]];
NSDate *currentTime = [NSDate date];

NSLog(@"DateOfBirth======%@",DateOfBirth);

NSInteger years = [[[NSCalendar currentCalendar] components:NSYearCalendarUnit
                                                   fromDate:DateOfBirth
                                                     toDate:currentTime options:0]year];

NSInteger months = [[[NSCalendar currentCalendar] components:NSMonthCalendarUnit
                                                    fromDate:DateOfBirth
                                                      toDate:currentTime options:0]month];
NSLog(@"Number of years: %d",years);
NSLog(@"Number of Months: %d,",months);



    return years;
  // End of Method
  }

【讨论】：

【解决方案10】：

这是一个计算年龄的函数（Swift 2.1）

func calculateAge (birthday: NSDate) -> NSInteger {

    let calendar : NSCalendar = NSCalendar.currentCalendar()
    let unitFlags : NSCalendarUnit = [NSCalendarUnit.Year, NSCalendarUnit.Month, NSCalendarUnit.Day]
    let dateComponentNow : NSDateComponents = calendar.components(unitFlags, fromDate: NSDate())
    let dateComponentBirth : NSDateComponents = calendar.components(unitFlags, fromDate: birthday)

    if ( (dateComponentNow.month < dateComponentBirth.month) ||
        ((dateComponentNow.month == dateComponentBirth.month) && (dateComponentNow.day < dateComponentBirth.day))
        )
    {
        return dateComponentNow.year - dateComponentBirth.year - 1
    }
    else {
        return dateComponentNow.year - dateComponentBirth.year
    }
}

【讨论】：

【解决方案11】：

let birthday = NSCalendar.currentCalendar().dateWithEra(1, year: 2016, month: 07, day: 25, hour: 8, minute: 53, second: 0, nanosecond: 0)!

func calculateAge(birthday: NSDate) -> String {

func grammaticalString(forUnit unit: String, value: Int) -> String {
    if value > 1 {
        return "\(value) \(unit)s"
    } else {
        return "\(value) \(unit)"
    }
}

let calendar = NSCalendar.currentCalendar()
let unitFlags: NSCalendarUnit = [NSCalendarUnit.Year, NSCalendarUnit.Month, NSCalendarUnit.Day, NSCalendarUnit.Hour, NSCalendarUnit.Minute]

let ageComponent = calendar.components(unitFlags, fromDate: birthday, toDate: NSDate(), options: [])
let years = ageComponent.year
let months = ageComponent.month
let days = ageComponent.day
let hours = ageComponent.hour

switch (years, months, days, hours) {
    case (let y, let m, _, _) where y > 0:
        return "\(grammaticalString(forUnit: "Year", value: y)) \(grammaticalString(forUnit: "Month", value: m))"

    case (let y, let m, let d, _) where y == 0 && m > 0:
        return "\(grammaticalString(forUnit: "Month", value: m)) \(grammaticalString(forUnit: "Day", value: d))"

    case (let y, let m, let d, _) where y == 0 && m == 0 && d > 0:
        return "\(grammaticalString(forUnit: "Day", value: d))"

    case (let y, let m, let d, let h) where y == 0 && m == 0 && d == 0 && h > 0:
        return "\(grammaticalString(forUnit: "Hour", value: h))"

    case (let y, let m, let d, let h) where y == 0 && m == 0 && d == 0 && h == 0:

        if ageComponent.minute > 0 {
            return "\(grammaticalString(forUnit: "Minute", value: ageComponent.minute))"
        } else {
            return "-"
        }

    default:
        return "-"
}

}

// Output will be any of these
// 2 Years 3 Months
// 3 Months 0 Days
// 2 Days
// 3 Hours
// 45 Minutes
// -

【讨论】：