Groupby 使用 PIVOT

Question

我有这张桌子：

Person  Job
PersonA XX
PersonA XX
PersonA XX
PersonB XX
PersonB XX
PersonB YY
PersonB ZZ
PersonC XX
PersonC XX
PersonA XX
PersonA YY
PersonB ZZ
...

现在，我希望输出是这样的：

Job PersonA PersonB Person C
XX  4       2       2
YY  1       1       0
ZZ  0       2       0

到目前为止，我有这个：

SELECT DISTINCT Person,
                       (SELECT COUNT(Job)
                        FROM dbo.TableName
                        GROUP BY Job)
FROM dbo.ExcelImport

不走运:(

Answer 1

你应该尝试这样的事情：

select
    Job
    ,SUM(case when Person = 'PersonA'
        then
            1
        else
            0
    end) as 'PersonA'
    ,SUM(case when Person = 'PersonB'
        then
            1
        else
            0
    end) as 'PersonB'
    ,SUM(case when Person = 'PersonC'
        then
            1
        else
            0
    end) as 'PersonC'
from
    TableName
group by
    Job

Answer 2

pivot 操作员的任务很简单：

select *
from (select Job as Job2, * from [TableName]) t
    pivot (count(Job2) for Person in ([PersonA],[PersonB],[PersonC])) p

Answer 3

你也可以使用枢轴

select * from per
pivot (count(job)  for job in ([xx],[yy],[zz]))

Answer 4

如果人是固定的，试试这个

SELECT * FROM Table1
PIVOT
(
    COUNT([Person]) FOR [Person] IN ([PersonA],[PersonB],[PersonC])
) p

SQL FIDDLE DEMO

如果人不同，那么试试这个动态查询

DECLARE @cols AS NVARCHAR(MAX), @query  AS NVARCHAR(MAX)
SELECT @cols = STUFF((SELECT distinct ',' + QUOTENAME([Person]) 
                    from Table1
            FOR XML PATH(''), TYPE
            ).value('.', 'NVARCHAR(MAX)') 
        ,1,1,'')

SET @query = 'SELECT [Job],' + @cols + ' 
             FROM
             (
                Select *
                FROM Table1
             ) T
             PIVOT
             (
                COUNT([Person])
                FOR [Person] IN (' + @cols + ')
             ) pvt '

EXECUTE(@query);