mysql - 组，但显示列的所有行答案

【问题标题】：mysql - group, but show all row of a columnmysql - 组，但显示列的所有行
【发布时间】：2013-01-26 05:30:26
【问题描述】：

我想对字段进行分组，但想显示名为 remain 的列的所有行：

这是未分组的当前输出：

并按组输出：

我在分组时想要这个：

这里是mysql查询：

SELECT staff.name,
  staff.designation_id_designation,
  staff.status_id_status,
  Concat_Ws('=', leave_remain.leave_type_id_leave_type, leave_remain.days) AS
  remain
FROM staff INNER JOIN
  leave_remain ON staff.id_staff = leave_remain.staff_id_staff
GROUP BY staff.name

【问题讨论】：

标签： mysql sql group-by concat

【解决方案1】：

使用GROUP_CONCAT

SELECT  staff.name,
        staff.designation_id_designation,
        staff.status_id_status,
        GROUP_CONCAT(Concat_Ws('=', leave_remain.leave_type_id_leave_type, leave_remain.days)) AS remain
FROM    staff 
        INNER JOIN leave_remain 
            ON staff.id_staff = leave_remain.staff_id_staff
GROUP   BY staff.name, staff.designation_id_designation, staff.status_id_status

SQLFiddle Demo

其他链接

MySQL GROUP_CONCAT

【讨论】：

将所有数字转成字符串，Concat_Ws('=', CAST(leave_remain.leave_type_id_leave_type AS VARCHAR(30)), CAST(leave_remain.days AS VARCHAR(30)))
你用的是什么版本的mysql？
哦这是语法错误，应该是CHAR 而不是VARCHAR sqlfiddle.com/#!2/729f7/7
再次感谢您的宝贵时间，愿上帝保佑您

【解决方案2】：

试试这个：

SELECT staff.name,
  staff.designation_id_designation,
  staff.status_id_status,
  GROUP_CONCAT(Concat_Ws('=', leave_remain.leave_type_id_leave_type, leave_remain.days) SEPARATOR ' ') AS remain
FROM staff INNER JOIN
  leave_remain ON staff.id_staff = leave_remain.staff_id_staff
GROUP BY staff.designation_id_designation,
         staff.name,
         staff.status_id_status;

【讨论】：

【解决方案3】：

为此，我们需要使用 group_contact 以“”分隔。

SELECT staff.name,
  staff.designation_id_designation,
  staff.status_id_status,
  GROUP_CONCAT(Concat_Ws('=', leave_remain.leave_type_id_leave_type, leave_remain.days) SEPARATOR ' ') AS remain
FROM staff 
INNER JOIN
  leave_remain 
ON 
staff.id_staff = leave_remain.staff_id_staff
GROUP BY staff.designation_id_designation,
         staff.name,
         staff.status_id_status;

【讨论】：