【发布时间】:2020-10-19 09:26:58
【问题描述】:
下面是我的桌子:
id order_number order_date order_details
---------------------------------------------
1 222 01-01-2020 44
2 222 02-01-2020 66
3 222 03-01-2020 20
4 223 03-01-2020 33
5 224 04-01-2020 55
6 225 02-01-2020 77
我想要 sum(order_details) where order_number = 222
喜欢这张桌子
order_date sum_order_details
----------------------------------
01-01-2020 130
02-01-2020 130
03-01-2020 130
我尝试了以下方法,但它不起作用
select order_number , order_date , sum(order_details) sum_orders from ex
group by order_number
having order_number = 222
【问题讨论】:
标签: sql-server sum duplicates