计算不同的多列

Question

我有按月输入的记录...这是当前查询提取全年结果的样子。请注意，这是一个 Oracle 数据库。

我的查询：

SELECT UMEMBERID, FIRSTNAME, LASTNAME, BIRTHDATE, PUBLICATIONDT
  FROM MY_TABLE
 WHERE INDENTIFIER IN ('GROUP1') 
  AND PUBLICATIONDT >= DATE'2014-01-01'
  AND PUBLICATIONDT <= DATE'2014-12-31'

实际返回结果：

 UMEMBERID | FIRSTNAME | LASTNAME | BIRTHDATE | PUBLICATIONDT
--------------------------------------------------------------
 1         | John      | Smith    | 6/26/1983 | 11/20/2014
 2         | Jane      | Smith    | 2/2/1980  | 11/21/2014
 3         |  Roger    | Rabbit   | 8/3/1982  | 11/20/2014
 4         |  Bugs     | Bunny    | 6/20/1983 | 11/19/2014
 5         |  Daffy    | Duck     | 4/3/1982  | 11/17/2014
 6         |  Winnie   | Pooh     | 2/27/1989 | 12/15/2014
 7         |  Jane     | Doe      | 8/5/1959  | 12/11/2014
 5         |  Daffy    | Duck     | 4/3/1982  | 12/9/2014
 3         |  Roger    | Rabbit   | 8/3/1982  | 12/9/2014
 10        |  John     | Doe      | 8/9/1992  | 12/18/2014

我的预期结果如下：

 UMEMBERID | FIRSTNAME | LASTNAME | BIRTHDATE | PUBLICATIONDT
--------------------------------------------------------------
 1         | John      | Smith    | 6/26/1983 | 11/20/2014
 2         | Jane      | Smith    | 2/2/1980  | 11/21/2014
 3         | Roger     | Rabbit   | 8/3/1982  | 12/09/2014
 4         | Bugs      | Bunny    | 6/20/1983 | 11/19/2014
 5         | Daffy     | Duck     | 4/3/1982  | 12/09/2014
 6         | Winnie    | Pooh     | 2/27/1989 | 12/15/2014
 7         | Jane      | Doe      | 8/5/1959  | 12/11/2014
 10        | John      | Doe      | 8/9/1992  | 12/18/2014

如果您在实际返回的结果中注意到它为每只 Roger Rabbit（11/20/2014 和 12/09/2014）和 Daffy Duck（11/17/2014 和 12/09/2014）拾取了额外的记录。在我的预期结果中，我只想获取 12/09/2015 日期并显示 8 条记录。

Answer 1

试试这样的：

SELECT UMEMBERID, FIRSTNAME, LASTNAME, BIRTHDATE, MAX(PUBLICATIONDT)
FROM MY_TABLE
WHERE INDENTIFIER IN ('GROUP1') 
AND PUBLICATIONDT >= DATE'2014-01-01'
AND PUBLICATIONDT <= DATE'2014-12-31'
GROUP BY UMEMBERID, FIRSTNAME, LASTNAME, BIRTHDATE;