【发布时间】:2018-05-03 05:46:23
【问题描述】:
我有两个名为
的表class_record_hist 将存储特定日期的班级出勤记录
student_record_hist 将存储特定班级的学生出勤列表。这里 transaction_id 将是两个表的主键
我的数据看起来像这样
Working_date STUDENT_NAME STUDENT_STATUS ATTENDANCE_CODE TEACHER_UPDATE TRANSACTION_ID
------------- ------------ -------------- --------------- -------------- --------------
2017-11-10 10:00:00 JAMES ABSENT 2344 AB 23453
2017-11-10 10:00:00 PETER ABSENT 2344 AB 23453
2017-11-10 10:00:00 MURPHY PRESENT 1001 PR 23453
2017-11-10 10:00:00 MICA PRESENT 1001 PR 23453
2017-11-10 10:00:00 STELLA PRESENT 1001 PR 23453
2017-11-10 10:00:00 STEPHEN PRESENT 1001 PR 23453
2017-11-10 10:00:00 TRACY PRESENT 1001 PR 23453
2017-11-10 14:00:00 JAMES PRESENT 1001 PR 23454
2017-11-10 14:00:00 PETER PRESENT 1001 PR 23454
2017-11-10 14:00:00 MURPHY PRESENT 1001 PR 23454
2017-11-10 14:00:00 MICA PRESENT 1001 PR 23454
2017-11-10 14:00:00 STELLA PRESENT 1001 PR 23454
2017-11-10 14:00:00 STEPHEN PRESENT 1001 PR 23454
2017-11-10 14:00:00 TRACY ABSENT 2344 AB 23454
2017-11-11 11:24:00 JAMES PRESENT 1001 PR 23454
2017-11-11 11:24:00 PETER PRESENT 1001 PR 23454
2017-11-11 11:24:00 MURPHY PRESENT 1001 PR 23454
2017-11-11 11:24:00 MICA PRESENT 1001 PR 23454
2017-11-11 11:24:00 STELLA PRESENT 1001 PR 23454
2017-11-11 11:24:00 STEPHEN PRESENT 1001 PR 23454
2017-11-11 11:24:00 TRACY PRESENT 1001 PR 23454
2017-11-11 14:24:00 JAMES ABSENT 2344 AB 23454
2017-11-11 14:24:00 PETER ABSENT 2344 AB 23454
2017-11-11 14:24:00 MURPHY ABSENT 2344 AB 23454
2017-11-11 14:24:00 MICA ABSENT 2344 AB 23454
2017-11-11 14:24:00 STELLA ABSENT 2344 AB 23454
2017-11-11 14:24:00 STEPHEN PRESENT 1001 PR 23454
2017-11-11 14:24:00 TRACY PRESENT 1001 PR 23454
我将根据这些记录生成报告
这是我的查询
select * from
(
select student_name, student_status,attendance_code,
working_date,class_id from
(
select to_char(a.date_tm,'yyyy-mm-dd hh24:mi:ss') AS working_date,
b.student_name,b.student_status,b.attendance_code,
b.teacher_update,a.transaction_id
from class_record_hist a,student_record_hist b
where a.school = 'DON BOSCO'
and a.building = 'A1'
and a.class_id = 'DB-3452'
and a.date_tm >= to_date('2017-11-10 06:00:00','yyyy-mm-dd hh24:mi:ss')
and a.date_tm <= to_date('2017-11-11 18:00:00','yyyy-mm-dd hh24:mi:ss')
and a.transaction_id = b.transaction_id
order by working_date desc,b.student_name asc
)
)
PIVOT
(
max(attendance_code) as code,
max(student_status) as status
for student_name in ('JAMES','PETER','MURPHY','MICA','STELLA','STEPHEN','TRACY');
) ;
结果:
WORKING_DATE CLASS_ID JAMES_STATUS JAMES_CODE PETER_STATUS PETER_CODE MURPHY_STATUS MURPHY_CODE MICA_STATUS MICA_CODE STELLA_STATUS STELLA_CODE STEPHEN_STATUS STEPHEN_CODE TRACY_STATUS TRACY_CODE
------------ -------- ------------ ---------- ------------ ---------- ------------- ----------- ----------- --------- ------------- ----------- -------------- ------------ ------------ ----------
2017-11-10 10:00:00 DB-3452 PRESENT 2344 PRESENT 2344 PRESENT 1001 PRESENT 1001 PRESENT 1001 PRESENT 1001 PRESENT 1001
2017-11-10 14:00:00 DB-3452 PRESENT 1001 PRESENT 1001 PRESENT 1001 PRESENT 1001 PRESENT 1001 PRESENT 1001 PRESENT 2344
2017-11-11 11:24:00 DB-3452 PRESENT 1001 PRESENT 1001 PRESENT 1001 PRESENT 1001 PRESENT 1001 PRESENT 1001 PRESENT 1001
2017-11-11 14:24:00 DB-3452 PRESENT 2344 PRESENT 2344 PRESENT 2344 PRESENT 2344 PRESENT 2344 PRESENT 1001 PRESENT 1001
从上面的结果可以看出数据不正确。
假设 James 有两个会话缺席,从他的代码 2344 可以看出,但状态仍显示为 Present。同样的问题发生在整个记录集。
我做错了什么?
非常感谢任何建议和意见?
【问题讨论】:
标签: oracle oracle11g pivot oracle-sqldeveloper oracle12c