Jsoup解析（正则表达式）

Question

您能否建议我如何使用 jsoup 提取这些消息：

资源/音频/歌曲/73742facb924e6.mp3

未来就是现在

绿灰色

从此代码：

<div class="playlist-item" 
    id="playlist-item-2" 
    data-song-id="8365" 
     
    onmouseover="javascript: pageUtils.playlistItemSharebar(2);"
    onclick="jwPlayerUtils.playSong(8365, 2, event); _gaq.push(['_setAccount', 'UA-1091709-7']); _gaq.push(['_trackPageview']);">
    
    <input type="hidden" id="song-path-8365" value="resources/audio/songs/73742facb924e6.mp3" />
    <input type="hidden" id="song-mode-8365" value="song" />
    <input type="hidden" id="song-name-left-8365" value="Future Is Now" />
    <input type="hidden" id="song-name-right-8365" value="Green Grey" />
    <input type="hidden" id="song-programName-8365" value="" />
        <input type="hidden" id="song-img-8365" value="resources/img/songs/98x74_DIR/8365.jpg?201702161231" />
    

这是我已经尝试过的：

 Document document = Jsoup.connect(url).execute().parse();

        Elements elements = document.select(".playlist-item");
        for (Element element : elements) {
            System.out.println("Artist: " + element.select("[id~=^song-name-right-[0-9]+$]").select("[value]"));
            System.out.println("Song: " + element.select("[id~=^song-name-left-[0-9]+$]").select("[value]"));;
            System.out.println("Link: " + element.select("[id~=^song-path-[0-9]+$]").select("[value]"));
        }

但结果是完整的字符串：

input type="hidden" id="song-path-8365" value="resources/audio/songs/73742facb924e6.mp3" /> input type="hidden" id="song-name-left-8365" value="Future Is Now" /> input type="hidden" id="song-name-right-8365" value="Green Grey" />

我确信还有其他一些（更简单、更正确）的方法可以解决这个问题，因此将不胜感激

Answer 1

Elements inputs = document.select("input");
for(Element input:inputs){
    System.out.println(input.attr("value"));
}