【问题标题】:How to Convert List<Object> to Json | C#如何将 List<Object> 转换为 Json | C#
【发布时间】:2020-09-15 12:41:02
【问题描述】:

我有一个由对象组成的列表,每个对象有 5 个数据。我需要将该列表转换为 json,但使用序列化它会填满空的 json。

有谁知道我做错了什么?

foreach (DataRow dtRow in dtAlarmas.Rows)
                {
                    String Name = dtRow["Name"].ToString();
                    String ID = dtRow["ID"].ToString();
                    String AlarmText = dtRow["AlarmText"].ToString();
                    String AlarmTimeNoNula = dtRow["AlarmTimeNoNula"].ToString();
                    lstAlarmasNoTratadas.Add(new Ondoan.DatosAux.Alarmas.AlarmaNoTratadaModel(dtRow["Name"].ToString(), Convert.ToInt32(dtRow["ID"]), dtRow["Class"].ToString(), dtRow["AlarmText"].ToString(), dtRow["AlarmTimeNoNula"].ToString()));
                }

                string sParams = JsonConvert.SerializeObject(lstAlarmasNoTratadas);

sParams 转换后的值 = "[{}]"

类 Ondoan.DatosAux.Alarmas.AlarmaNoTratadaModel

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

namespace Ondoan.DatosAux.Alarmas
{
   public class AlarmaNoTratadaModel
    {
        private string Name;
        private int ID;
        private string Class;
        private string AlarmText;
        private string AlarmaTimeNoNula;

        public AlarmaNoTratadaModel(string Name, int ID, string Class, string AlarmText, string AlarmaTimeNoNula)
       {
           // TODO: Complete member initialization
           this.Name = Name;
           this.ID = ID;
           this.Class = Class;
           this.AlarmText = AlarmText;
           this.AlarmaTimeNoNula = AlarmaTimeNoNula;
       }

        public class AlarmaNoTratadasModel
        {
            public AlarmaNoTratadasModel() { }
            public AlarmaNoTratadasModel(String Name, Nullable<System.Int32> ID, String Class, String AlarmText, String AlarmaTimeNoNula)
            {
                this.Name = Name;
                this.ID = ID;
                this.Class = Class;
                this.AlarmText = AlarmText;
                this.AlarmaTimeNoNula = AlarmaTimeNoNula.ToString();
            }

            public System.String Name { get; set; }
            public Nullable<System.Int32> ID { get; set; }
            public System.String Class { get; set; }
            public System.String AlarmText { get; set; }
            public System.String AlarmaTimeNoNula { get; set; }
        }
    }
}

【问题讨论】:

标签: c# json list serialization converters


【解决方案1】:

问题是 JsonConvert 默认不序列化私有字段。将它们设为公共属性或添加 JsonPropertyAttribute。

[JsonProperty]
private string Name;
[JsonProperty]
private int ID;
[JsonProperty]
private string Class;
[JsonProperty]
private string AlarmText;
[JsonProperty]
private string AlarmaTimeNoNula;

【讨论】:

    猜你喜欢
    • 1970-01-01
    • 2014-09-09
    • 2019-05-08
    • 1970-01-01
    • 1970-01-01
    • 2023-03-08
    • 2017-04-07
    • 1970-01-01
    相关资源
    最近更新 更多