【问题标题】:How to store a spark DataFrame as CSV into Azure Blob Storage如何将 Spark DataFrame 作为 CSV 存储到 Azure Blob 存储中
【发布时间】:2020-04-16 08:35:52
【问题描述】:

我正在尝试将 Spark DataFrame 作为 CSV 从本地 Spark 群集存储在 Azure Blob 存储中

首先,我使用 Azure 帐户/帐户密钥设置配置(我不确定什么是正确的配置,所以我已经设置了所有这些)

sparkContext.getConf.set(s"fs.azure.account.key.${account}.blob.core.windows.net", accountKey)

sparkContext.hadoopConfiguration.set(s"fs.azure.account.key.${account}.dfs.core.windows.net", accountKey)
    sparkContext.hadoopConfiguration.set(s"fs.azure.account.key.${account}.blob.core.windows.net", accountKey)

然后我尝试使用以下内容存储 CSV

filePath = s"wasbs://${container}@${account}.blob.core.windows.net/${prefix}/${filename}"
dataFrame.coalesce(1)
  .write.format("csv")
  .options(Map(
    "header" -> (if (hasHeader) "true" else "false"),
    "sep" -> delimiter,
    "quote" -> quote
  ))
  .save(filePath)

但是这会因Job aborted 和以下堆栈跟踪而失败

org.apache.spark.sql.execution.datasources.FileFormatWriter$.write(FileFormatWriter.scala:196)
org.apache.spark.sql.execution.datasources.InsertIntoHadoopFsRelationCommand.run(InsertIntoHadoopFsRelationCommand.scala:159)
org.apache.spark.sql.execution.command.DataWritingCommandExec.sideEffectResult$lzycompute(commands.scala:104)
org.apache.spark.sql.execution.command.DataWritingCommandExec.sideEffectResult(commands.scala:102)
org.apache.spark.sql.execution.command.DataWritingCommandExec.doExecute(commands.scala:122)
org.apache.spark.sql.execution.SparkPlan$$anonfun$execute$1.apply(SparkPlan.scala:131)
org.apache.spark.sql.execution.SparkPlan$$anonfun$execute$1.apply(SparkPlan.scala:127)
org.apache.spark.sql.execution.SparkPlan$$anonfun$executeQuery$1.apply(SparkPlan.scala:155)
org.apache.spark.rdd.RDDOperationScope$.withScope(RDDOperationScope.scala:151)
org.apache.spark.sql.execution.SparkPlan.executeQuery(SparkPlan.scala:152)
org.apache.spark.sql.execution.SparkPlan.execute(SparkPlan.scala:127)
org.apache.spark.sql.execution.QueryExecution.toRdd$lzycompute(QueryExecution.scala:80)
org.apache.spark.sql.execution.QueryExecution.toRdd(QueryExecution.scala:80)
org.apache.spark.sql.DataFrameWriter$$anonfun$runCommand$1.apply(DataFrameWriter.scala:668)
org.apache.spark.sql.DataFrameWriter$$anonfun$runCommand$1.apply(DataFrameWriter.scala:668)
org.apache.spark.sql.execution.SQLExecution$$anonfun$withNewExecutionId$1.apply(SQLExecution.scala:78)
org.apache.spark.sql.execution.SQLExecution$.withSQLConfPropagated(SQLExecution.scala:125)
org.apache.spark.sql.execution.SQLExecution$.withNewExecutionId(SQLExecution.scala:73)
org.apache.spark.sql.DataFrameWriter.runCommand(DataFrameWriter.scala:668)
org.apache.spark.sql.DataFrameWriter.saveToV1Source(DataFrameWriter.scala:276)
org.apache.spark.sql.DataFrameWriter.save(DataFrameWriter.scala:270)
org.apache.spark.sql.DataFrameWriter.save(DataFrameWriter.scala:228)

但是当我查看 blob 容器时,我可以看到我的文件,但是我无法在 Spark DataFrame 中读回它,我收到此错误 Unable to infer schema for CSV. It must be specified manually.; 并遵循堆栈跟踪

org.apache.spark.sql.execution.datasources.DataSource$$anonfun$7.apply(DataSource.scala:185)
org.apache.spark.sql.execution.datasources.DataSource$$anonfun$7.apply(DataSource.scala:185)
scala.Option.getOrElse(Option.scala:121)
org.apache.spark.sql.execution.datasources.DataSource.getOrInferFileFormatSchema(DataSource.scala:184)
org.apache.spark.sql.execution.datasources.DataSource.resolveRelation(DataSource.scala:373)
org.apache.spark.sql.DataFrameReader.loadV1Source(DataFrameReader.scala:223)
org.apache.spark.sql.DataFrameReader.load(DataFrameReader.scala:211)
org.apache.spark.sql.DataFrameReader.load(DataFrameReader.scala:178)

好像问题已经在Databricks forum上报告了!!

在 Azure Blob 上存储 DataFrame 的正确方法是什么?

【问题讨论】:

    标签: scala azure apache-spark apache-spark-sql azure-blob-storage


    【解决方案1】:

    原来在作业失败之前有一个内部错误

    Caused by: java.lang.NoSuchMethodError: com.microsoft.azure.storage.blob.CloudBlob.startCopyFromBlob(Ljava/net/URI;Lcom/microsoft/azure/storage/AccessCondition;Lcom/microsoft/azure/storage/AccessCondition;Lcom/microsoft/azure/storage/blob/BlobRequestOptions;Lcom/microsoft/azure/storage/OperationContext;)Ljava/lang/String;
        at org.apache.hadoop.fs.azure.StorageInterfaceImpl$CloudBlobWrapperImpl.startCopyFromBlob(StorageInterfaceImpl.java:399)
        at org.apache.hadoop.fs.azure.AzureNativeFileSystemStore.rename(AzureNativeFileSystemStore.java:2449)
        at org.apache.hadoop.fs.azure.AzureNativeFileSystemStore.rename(AzureNativeFileSystemStore.java:2372)
        at org.apache.hadoop.fs.azure.NativeAzureFileSystem$NativeAzureFsOutputStream.restoreKey(NativeAzureFileSystem.java:918)
        at org.apache.hadoop.fs.azure.NativeAzureFileSystem$NativeAzureFsOutputStream.close(NativeAzureFileSystem.java:819)
        at org.apache.hadoop.fs.FSDataOutputStream$PositionCache.close(FSDataOutputStream.java:72)
        at org.apache.hadoop.fs.FSDataOutputStream.close(FSDataOutputStream.java:106)
        at sun.nio.cs.StreamEncoder.implClose(StreamEncoder.java:320)
        at sun.nio.cs.StreamEncoder.close(StreamEncoder.java:149)
        at java.io.OutputStreamWriter.close(OutputStreamWriter.java:233)
        at com.univocity.parsers.common.AbstractWriter.close(AbstractWriter.java:876)
        ... 18 more
    

    在使用实际数据创建临时文件后,它会尝试将文件移动到用户使用CloudBlob.startCopyFromBlob 指定的位置。像往常一样,microsft 人通过将此方法重命名为 CloudBlob.startCopy 来打破这一点。

    我正在使用"org.apache.hadoop" % "hadoop-azure" % "3.2.1",它是"hadoop-azure" 的最新版本,它似乎与旧的startCopyFromBlob 保持一致,所以 我需要使用具有此方法的旧 azure-storage 版本,可能是 2.x.x。

    见https://github.com/Azure/azure-storage-java/issues/113

    【讨论】:

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