【发布时间】:2020-04-16 08:35:52
【问题描述】:
我正在尝试将 Spark DataFrame 作为 CSV 从本地 Spark 群集存储在 Azure Blob 存储中
首先,我使用 Azure 帐户/帐户密钥设置配置(我不确定什么是正确的配置,所以我已经设置了所有这些)
sparkContext.getConf.set(s"fs.azure.account.key.${account}.blob.core.windows.net", accountKey)
sparkContext.hadoopConfiguration.set(s"fs.azure.account.key.${account}.dfs.core.windows.net", accountKey)
sparkContext.hadoopConfiguration.set(s"fs.azure.account.key.${account}.blob.core.windows.net", accountKey)
然后我尝试使用以下内容存储 CSV
filePath = s"wasbs://${container}@${account}.blob.core.windows.net/${prefix}/${filename}"
dataFrame.coalesce(1)
.write.format("csv")
.options(Map(
"header" -> (if (hasHeader) "true" else "false"),
"sep" -> delimiter,
"quote" -> quote
))
.save(filePath)
但是这会因Job aborted 和以下堆栈跟踪而失败
org.apache.spark.sql.execution.datasources.FileFormatWriter$.write(FileFormatWriter.scala:196)
org.apache.spark.sql.execution.datasources.InsertIntoHadoopFsRelationCommand.run(InsertIntoHadoopFsRelationCommand.scala:159)
org.apache.spark.sql.execution.command.DataWritingCommandExec.sideEffectResult$lzycompute(commands.scala:104)
org.apache.spark.sql.execution.command.DataWritingCommandExec.sideEffectResult(commands.scala:102)
org.apache.spark.sql.execution.command.DataWritingCommandExec.doExecute(commands.scala:122)
org.apache.spark.sql.execution.SparkPlan$$anonfun$execute$1.apply(SparkPlan.scala:131)
org.apache.spark.sql.execution.SparkPlan$$anonfun$execute$1.apply(SparkPlan.scala:127)
org.apache.spark.sql.execution.SparkPlan$$anonfun$executeQuery$1.apply(SparkPlan.scala:155)
org.apache.spark.rdd.RDDOperationScope$.withScope(RDDOperationScope.scala:151)
org.apache.spark.sql.execution.SparkPlan.executeQuery(SparkPlan.scala:152)
org.apache.spark.sql.execution.SparkPlan.execute(SparkPlan.scala:127)
org.apache.spark.sql.execution.QueryExecution.toRdd$lzycompute(QueryExecution.scala:80)
org.apache.spark.sql.execution.QueryExecution.toRdd(QueryExecution.scala:80)
org.apache.spark.sql.DataFrameWriter$$anonfun$runCommand$1.apply(DataFrameWriter.scala:668)
org.apache.spark.sql.DataFrameWriter$$anonfun$runCommand$1.apply(DataFrameWriter.scala:668)
org.apache.spark.sql.execution.SQLExecution$$anonfun$withNewExecutionId$1.apply(SQLExecution.scala:78)
org.apache.spark.sql.execution.SQLExecution$.withSQLConfPropagated(SQLExecution.scala:125)
org.apache.spark.sql.execution.SQLExecution$.withNewExecutionId(SQLExecution.scala:73)
org.apache.spark.sql.DataFrameWriter.runCommand(DataFrameWriter.scala:668)
org.apache.spark.sql.DataFrameWriter.saveToV1Source(DataFrameWriter.scala:276)
org.apache.spark.sql.DataFrameWriter.save(DataFrameWriter.scala:270)
org.apache.spark.sql.DataFrameWriter.save(DataFrameWriter.scala:228)
但是当我查看 blob 容器时,我可以看到我的文件,但是我无法在 Spark DataFrame 中读回它,我收到此错误 Unable to infer schema for CSV. It must be specified manually.; 并遵循堆栈跟踪
org.apache.spark.sql.execution.datasources.DataSource$$anonfun$7.apply(DataSource.scala:185)
org.apache.spark.sql.execution.datasources.DataSource$$anonfun$7.apply(DataSource.scala:185)
scala.Option.getOrElse(Option.scala:121)
org.apache.spark.sql.execution.datasources.DataSource.getOrInferFileFormatSchema(DataSource.scala:184)
org.apache.spark.sql.execution.datasources.DataSource.resolveRelation(DataSource.scala:373)
org.apache.spark.sql.DataFrameReader.loadV1Source(DataFrameReader.scala:223)
org.apache.spark.sql.DataFrameReader.load(DataFrameReader.scala:211)
org.apache.spark.sql.DataFrameReader.load(DataFrameReader.scala:178)
好像问题已经在Databricks forum上报告了!!
在 Azure Blob 上存储 DataFrame 的正确方法是什么?
【问题讨论】:
标签: scala azure apache-spark apache-spark-sql azure-blob-storage