将图像上传到 azure blob 存储后如何返回图像的 url？答案

【问题标题】：How to return the url of an image after uploading it to azure blob storage?将图像上传到 azure blob 存储后如何返回图像的 url？
【发布时间】：2020-11-12 11:34:53
【问题描述】：

我是使用 azure blob sotorage 的新手，我希望在将图像保存到 azure blob 存储后返回其存储 url。

我的代码示例：

  const uploadImage = catchAsync(async (req, res) => {
  const blobName = getBlobName(req.file.originalname);
  const stream = getStream(req.file.buffer);
  const containerClient = blobServiceClient.getContainerClient(containerName);
  const blockBlobClient = containerClient.getBlockBlobClient(blobName);

  try {
    await blockBlobClient.uploadStream(stream,
      uploadOptions.bufferSize, uploadOptions.maxBuffers,
      { blobHTTPHeaders: { blobContentType: "image/jpeg" } });
      res.send(httpStatus.OK, { message: 'File uploaded to Azure Blob storage.' });
    } catch (err) {
      throw new ApiError(httpStatus.NOT_FOUND, { message: err.message });
    }
});

【问题讨论】：

标签： node.js azure-blob-storage

【解决方案1】：

其实很简单。 BlockBlobClient 有一个名为 url 的属性，它是 blob 的 URL。你可以简单地返回它。

类似于下面的代码（虽然未经测试）：

  const uploadImage = catchAsync(async (req, res) => {
  const blobName = getBlobName(req.file.originalname);
  const stream = getStream(req.file.buffer);
  const containerClient = blobServiceClient.getContainerClient(containerName);
  const blockBlobClient = containerClient.getBlockBlobClient(blobName);

  try {
    await blockBlobClient.uploadStream(stream,
      uploadOptions.bufferSize, uploadOptions.maxBuffers,
      { blobHTTPHeaders: { blobContentType: "image/jpeg" } });
      res.send(httpStatus.OK, { blobUrl: blockBlobClient.url, message: 'File uploaded to Azure Blob storage.' });
    } catch (err) {
      throw new ApiError(httpStatus.NOT_FOUND, { message: err.message });
    }
});

【讨论】：