ui-grid 使用外部分页和导出数据

Question

我目前正在使用通过外部分页实现的 ui-grid 来显示我的数据。我遇到了只能导出当前查看的数据的问题，但是我也需要能够导出所有数据。

有人知道使用外部分页导出所有数据的解决方法吗？

Answer 1

我最终使用了 ui-grid 附带的 csvExport 函数。我添加了一个“全部导出”自定义菜单项，效果很好！这是我的代码：

gridMenuCustomItems: [
                      {
                        title: 'Export All',
                        action: function ($event) {

                                $http.get(url).success(function(data) {
                                    $scope.gridOptions.totalItems = data.totalFeatures;
                                    $scope.gridOptions.data = data.features;
                                    $timeout(function()
                                            {
                                                var myElement = angular.element(document.querySelectorAll(".custom-csv-link-location"));
                                                $scope.gridApi.exporter.csvExport( uiGridExporterConstants.ALL, uiGridExporterConstants.ALL, myElement );
                                            }, 1000);

                                    });                                                                                                                                                                     
                        }
                      }
                    ]

希望这对某人有所帮助！

Answer 2

好的，所以我以 ui-grids 服务器端示例并稍微修改了他们的 plnkr。我只是在 ui-grid 之外创建了一个按钮，该按钮调用您的数据源，它将 json 转换为 CSV 并下载文件

http://plnkr.co/edit/xK3TYtKANuci0kUgGacQ?p=preview

<button ng-click="exportAllData()">Export Data</button>

然后在你的控制器中：

$scope.exportAllData = function()
{
  setTimeout(function()
  {
    $http.get('largeLoad.json').success(function(response)
    {       
      $scope.JSONToCSVConvertor(response, "Data Title", true);
    }); 
  },100);
};

$scope.JSONToCSVConvertor = function(JSONData, ReportTitle, ShowLabel)
{
  //If JSONData is not an object then JSON.parse will parse the JSON string in an Object
  var arrData = typeof JSONData != 'object' ? JSON.parse(JSONData) : JSONData;

  var CSV = '';    
  //Set Report title in first row or line

  CSV += ReportTitle + '\r\n\n';

  //This condition will generate the Label/Header
  if (ShowLabel) {
      var row = "";

      //This loop will extract the label from 1st index of on array
      for (var index in arrData[0]) {

          //Now convert each value to string and comma-seprated
          row += index + ',';
      }

      row = row.slice(0, -1);

      //append Label row with line break
      CSV += row + '\r\n';
  }

  //1st loop is to extract each row
  for (var i = 0; i < arrData.length; i++) {
      var row = "";

      //2nd loop will extract each column and convert it in string comma-seprated
      for (var index in arrData[i]) {
          row += '"' + arrData[i][index] + '",';
      }

      row.slice(0, row.length - 1);

      //add a line break after each row
      CSV += row + '\r\n';
  }

  if (CSV == '') {        
      alert("Invalid data");
      return;
  }   

  //Generate a file name
  var fileName = "MyReport_";
  //this will remove the blank-spaces from the title and replace it with an underscore
  fileName += ReportTitle.replace(/ /g,"_");   

  //Initialize file format you want csv or xls
  var uri = 'data:text/csv;charset=utf-8,' + escape(CSV);

  // Now the little tricky part.
  // you can use either>> window.open(uri);
  // but this will not work in some browsers
  // or you will not get the correct file extension    

  //this trick will generate a temp <a /> tag
  var link = document.createElement("a");    
  link.href = uri;

  //set the visibility hidden so it will not effect on your web-layout
  link.style = "visibility:hidden";
  link.download = fileName + ".csv";

  //this part will append the anchor tag and remove it after automatic click
  document.body.appendChild(link);
  link.click();
  document.body.removeChild(link);
}

JSONToCSVConverter() 来源：http://jsfiddle.net/hybrid13i/JXrwM/